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Point [tex]$M$[/tex] is the midpoint of segment [tex]$KL$[/tex]. Point [tex]$N$[/tex] is the midpoint of segment [tex]$ML$[/tex].

Point [tex]$K$[/tex] is located at [tex]$(-7, -6)$[/tex], and point [tex]$L$[/tex] is located at [tex]$(1, 10)$[/tex]. What are the coordinates of point [tex]$N$[/tex]?

A. [tex]$(-5, -2)$[/tex]
B. [tex]$(-1, 6)$[/tex]
C. [tex]$(-2, 6)$[/tex]
D. [tex]$(-3, 2)$[/tex]

Sagot :

To find the coordinates of point [tex]\( N \)[/tex], we'll follow a series of steps. We start with finding the coordinates of the midpoint [tex]\( M \)[/tex] of segment [tex]\( KL \)[/tex], and then use [tex]\( M \)[/tex] to find the midpoint [tex]\( N \)[/tex] of segment [tex]\( ML \)[/tex].

1. Determine the coordinates of the midpoint [tex]\( M \)[/tex] of segment [tex]\( KL \)[/tex].

Given:
[tex]\[ K = (-7, -6) \quad \text{and} \quad L = (1, 10) \][/tex]

The formula for the midpoint [tex]\( M \)[/tex] of a segment with endpoints [tex]\((x_1, y_1)\)[/tex] and [tex]\((x_2, y_2)\)[/tex] is:
[tex]\[ M = \left( \frac{x_1 + x_2}{2}, \frac{y_1 + y_2}{2} \right) \][/tex]

Plugging in the coordinates of [tex]\( K \)[/tex] and [tex]\( L \)[/tex]:
[tex]\[ M_x = \frac{-7 + 1}{2} = \frac{-6}{2} = -3 \][/tex]
[tex]\[ M_y = \frac{-6 + 10}{2} = \frac{4}{2} = 2 \][/tex]

Thus, the coordinates of point [tex]\( M \)[/tex] are:
[tex]\[ M = (-3, 2) \][/tex]

2. Determine the coordinates of the midpoint [tex]\( N \)[/tex] of segment [tex]\( ML \)[/tex].

Given:
[tex]\[ M = (-3, 2) \quad \text{and} \quad L = (1, 10) \][/tex]

Using the same midpoint formula:
[tex]\[ N = \left( \frac{M_x + L_x}{2}, \frac{M_y + L_y}{2} \right) \][/tex]

Plugging in the coordinates of [tex]\( M \)[/tex] and [tex]\( L \)[/tex]:
[tex]\[ N_x = \frac{-3 + 1}{2} = \frac{-2}{2} = -1 \][/tex]
[tex]\[ N_y = \frac{2 + 10}{2} = \frac{12}{2} = 6 \][/tex]

Thus, the coordinates of point [tex]\( N \)[/tex] are:
[tex]\[ N = (-1, 6) \][/tex]

Therefore, the coordinates of point [tex]\( N \)[/tex] are [tex]\((-1, 6)\)[/tex], which corresponds to answer choice [tex]\( \text{B} \)[/tex].