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Triangle [tex]$ABC$[/tex] is a right triangle with [tex]$\cos \left(22.6^{\circ}\right)=\frac{b}{13}$[/tex]. Solve for [tex]$b$[/tex] and round to the nearest whole number.

Which equation correctly uses the value of [tex]$b$[/tex] to solve for [tex]$a$[/tex]?

A. [tex]$\tan \left(22.6^{\circ}\right)=\frac{a}{13}$[/tex]
B. [tex]$\tan \left(22.6^{\circ}\right)=\frac{13}{a}$[/tex]
C. [tex]$\tan \left(22.6^{\circ}\right)=\frac{a}{12}$[/tex]
D. [tex]$\tan \left(22.6^{\circ}\right)=\frac{12}{a}$[/tex]


Sagot :

To solve the problem step-by-step, let’s break it down into two parts: finding [tex]\( b \)[/tex] and identifying the correct equation to use to solve for [tex]\( a \)[/tex].

Step 1: Solving for [tex]\( b \)[/tex]

We know that:
[tex]\[ \cos(22.6^\circ) = \frac{b}{13} \][/tex]

To isolate [tex]\( b \)[/tex], we multiply both sides of the equation by 13:
[tex]\[ b = 13 \cos(22.6^\circ) \][/tex]

Using a calculator, we find:
[tex]\[ \cos(22.6^\circ) \approx 0.9239 \][/tex]

Therefore:
[tex]\[ b = 13 \times 0.9239 \approx 12.0117 \][/tex]

Rounding [tex]\( 12.0117 \)[/tex] to the nearest whole number:
[tex]\[ b \approx 12 \][/tex]

Step 2: Identifying the correct equation to use for [tex]\( a \)[/tex]

We are provided with the following options for equations involving [tex]\( \tan(22.6^\circ) \)[/tex]:

1. [tex]\( \tan(22.6^\circ) = \frac{a}{13} \)[/tex]
2. [tex]\( \tan(22.6^\circ) = \frac{13}{a} \)[/tex]
3. [tex]\( \tan(22.6^\circ) = \frac{a}{12} \)[/tex]
4. [tex]\( \tan(22.6^\circ) = \frac{12}{a} \)[/tex]

To determine which equation is correct, let's recall the definitions and relationships of trigonometric functions in a right triangle. Specifically:
[tex]\[ \tan(\theta) = \frac{\text{opposite}}{\text{adjacent}} \][/tex]

In triangle [tex]\( ABC \)[/tex], with [tex]\( \angle B = 22.6^\circ \)[/tex]:
- The side opposite [tex]\( \angle B \)[/tex] is [tex]\( a \)[/tex].
- The side adjacent to [tex]\( \angle B \)[/tex] is [tex]\( b \approx 12 \)[/tex].

From trigonometric properties:
[tex]\[ \tan(22.6^\circ) = \frac{a}{\text{adjacent side}} \][/tex]

Given the choices and knowing that [tex]\( b \approx 12 \)[/tex]:
[tex]\[ \tan(22.6^\circ) = \frac{a}{12} \][/tex]

Thus, the correct equation is:
[tex]\[ \tan(22.6^\circ) = \frac{a}{12} \][/tex]

Therefore, the answer is:
[tex]\[ \boxed{\tan(22.6^\circ) = \frac{a}{12}} \][/tex]