Westonci.ca makes finding answers easy, with a community of experts ready to provide you with the information you seek. Join our platform to connect with experts ready to provide precise answers to your questions in various areas. Get precise and detailed answers to your questions from a knowledgeable community of experts on our Q&A platform.
Sagot :
To solve the problem step-by-step, let’s break it down into two parts: finding [tex]\( b \)[/tex] and identifying the correct equation to use to solve for [tex]\( a \)[/tex].
Step 1: Solving for [tex]\( b \)[/tex]
We know that:
[tex]\[ \cos(22.6^\circ) = \frac{b}{13} \][/tex]
To isolate [tex]\( b \)[/tex], we multiply both sides of the equation by 13:
[tex]\[ b = 13 \cos(22.6^\circ) \][/tex]
Using a calculator, we find:
[tex]\[ \cos(22.6^\circ) \approx 0.9239 \][/tex]
Therefore:
[tex]\[ b = 13 \times 0.9239 \approx 12.0117 \][/tex]
Rounding [tex]\( 12.0117 \)[/tex] to the nearest whole number:
[tex]\[ b \approx 12 \][/tex]
Step 2: Identifying the correct equation to use for [tex]\( a \)[/tex]
We are provided with the following options for equations involving [tex]\( \tan(22.6^\circ) \)[/tex]:
1. [tex]\( \tan(22.6^\circ) = \frac{a}{13} \)[/tex]
2. [tex]\( \tan(22.6^\circ) = \frac{13}{a} \)[/tex]
3. [tex]\( \tan(22.6^\circ) = \frac{a}{12} \)[/tex]
4. [tex]\( \tan(22.6^\circ) = \frac{12}{a} \)[/tex]
To determine which equation is correct, let's recall the definitions and relationships of trigonometric functions in a right triangle. Specifically:
[tex]\[ \tan(\theta) = \frac{\text{opposite}}{\text{adjacent}} \][/tex]
In triangle [tex]\( ABC \)[/tex], with [tex]\( \angle B = 22.6^\circ \)[/tex]:
- The side opposite [tex]\( \angle B \)[/tex] is [tex]\( a \)[/tex].
- The side adjacent to [tex]\( \angle B \)[/tex] is [tex]\( b \approx 12 \)[/tex].
From trigonometric properties:
[tex]\[ \tan(22.6^\circ) = \frac{a}{\text{adjacent side}} \][/tex]
Given the choices and knowing that [tex]\( b \approx 12 \)[/tex]:
[tex]\[ \tan(22.6^\circ) = \frac{a}{12} \][/tex]
Thus, the correct equation is:
[tex]\[ \tan(22.6^\circ) = \frac{a}{12} \][/tex]
Therefore, the answer is:
[tex]\[ \boxed{\tan(22.6^\circ) = \frac{a}{12}} \][/tex]
Step 1: Solving for [tex]\( b \)[/tex]
We know that:
[tex]\[ \cos(22.6^\circ) = \frac{b}{13} \][/tex]
To isolate [tex]\( b \)[/tex], we multiply both sides of the equation by 13:
[tex]\[ b = 13 \cos(22.6^\circ) \][/tex]
Using a calculator, we find:
[tex]\[ \cos(22.6^\circ) \approx 0.9239 \][/tex]
Therefore:
[tex]\[ b = 13 \times 0.9239 \approx 12.0117 \][/tex]
Rounding [tex]\( 12.0117 \)[/tex] to the nearest whole number:
[tex]\[ b \approx 12 \][/tex]
Step 2: Identifying the correct equation to use for [tex]\( a \)[/tex]
We are provided with the following options for equations involving [tex]\( \tan(22.6^\circ) \)[/tex]:
1. [tex]\( \tan(22.6^\circ) = \frac{a}{13} \)[/tex]
2. [tex]\( \tan(22.6^\circ) = \frac{13}{a} \)[/tex]
3. [tex]\( \tan(22.6^\circ) = \frac{a}{12} \)[/tex]
4. [tex]\( \tan(22.6^\circ) = \frac{12}{a} \)[/tex]
To determine which equation is correct, let's recall the definitions and relationships of trigonometric functions in a right triangle. Specifically:
[tex]\[ \tan(\theta) = \frac{\text{opposite}}{\text{adjacent}} \][/tex]
In triangle [tex]\( ABC \)[/tex], with [tex]\( \angle B = 22.6^\circ \)[/tex]:
- The side opposite [tex]\( \angle B \)[/tex] is [tex]\( a \)[/tex].
- The side adjacent to [tex]\( \angle B \)[/tex] is [tex]\( b \approx 12 \)[/tex].
From trigonometric properties:
[tex]\[ \tan(22.6^\circ) = \frac{a}{\text{adjacent side}} \][/tex]
Given the choices and knowing that [tex]\( b \approx 12 \)[/tex]:
[tex]\[ \tan(22.6^\circ) = \frac{a}{12} \][/tex]
Thus, the correct equation is:
[tex]\[ \tan(22.6^\circ) = \frac{a}{12} \][/tex]
Therefore, the answer is:
[tex]\[ \boxed{\tan(22.6^\circ) = \frac{a}{12}} \][/tex]
We appreciate your time. Please revisit us for more reliable answers to any questions you may have. We hope our answers were useful. Return anytime for more information and answers to any other questions you have. Stay curious and keep coming back to Westonci.ca for answers to all your burning questions.