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Select the correct answer.

What is the simplest equivalent form of this expression?

[tex]\sqrt[3]{\frac{8 x^6 y^9}{27 y^3 x^3}}[/tex]

A. [tex]\frac{2 x^3 y}{3 x}[/tex]

B. [tex]\frac{2 x^2 y^2}{3 x}[/tex]

C. [tex]\frac{2 x^5 y^2}{3 y^3 z^5}[/tex]

D. [tex]\frac{8 x^3 y^2}{27 x^3}[/tex]

Sagot :

To find the simplest equivalent form of the given expression:
[tex]\[ \sqrt[3]{\frac{8 x^6 y^9}{27 y^3 x^3}} \][/tex]
we'll perform the following steps:

1. Simplify the expression inside the cube root:
[tex]\[ \frac{8 x^6 y^9}{27 y^3 x^3} \][/tex]

2. Separate the coefficients and the variables:
[tex]\[ \frac{8}{27} \cdot \frac{x^6}{x^3} \cdot \frac{y^9}{y^3} \][/tex]

3. Simplify each part:
- For the coefficients:
[tex]\[ \frac{8}{27} \][/tex]
- For the [tex]\(x\)[/tex] terms:
[tex]\[ \frac{x^6}{x^3} = x^{6-3} = x^3 \][/tex]
- For the [tex]\(y\)[/tex] terms:
[tex]\[ \frac{y^9}{y^3} = y^{9-3} = y^6 \][/tex]

4. Combine the simplified parts:
[tex]\[ \frac{8}{27} \cdot x^3 \cdot y^6 \][/tex]

5. Apply the cube root to each part:
[tex]\[ \sqrt[3]{\frac{8}{27}} \cdot \sqrt[3]{x^3} \cdot \sqrt[3]{y^6} \][/tex]

6. Simplify the individual cube roots:
- For the coefficients:
[tex]\[ \sqrt[3]{\frac{8}{27}} = \frac{\sqrt[3]{8}}{\sqrt[3]{27}} = \frac{2}{3} \][/tex]
- For the [tex]\(x^3\)[/tex]:
[tex]\[ \sqrt[3]{x^3} = x \][/tex]
- For the [tex]\(y^6\)[/tex]:
[tex]\[ \sqrt[3]{y^6} = y^{6/3} = y^2 \][/tex]

7. Combine the results of the cube roots:
[tex]\[ \frac{2}{3} \cdot x \cdot y^2 = \frac{2 x y^2}{3} \][/tex]

Thus, the simplest equivalent form of the given expression is:
[tex]\[ \frac{2 x y^2}{3} \][/tex]

Now, compare this with the options provided:
A. [tex]\(\frac{2 x^3 y}{3 x}\)[/tex]

B. [tex]\(\frac{2 x^2 y^2}{3 x}\)[/tex]

C. [tex]\(\frac{2 x^5 y^2}{3 y^3 z^5}\)[/tex]

D. [tex]\(\frac{8 x^3 y^2}{27 x^3}\)[/tex]

We see that option B is the closest match when you simplify inside:
[tex]\[ \frac{2 x y^2}{3} \][/tex]

Therefore, the correct answer is:
[tex]\[ \boxed{\frac{2 x^2 y^2}{3 x}} \][/tex]

So, the final answer is:
[tex]\[ \boxed{B} \][/tex]