Westonci.ca is your go-to source for answers, with a community ready to provide accurate and timely information. Ask your questions and receive accurate answers from professionals with extensive experience in various fields on our platform. Discover detailed answers to your questions from a wide network of experts on our comprehensive Q&A platform.
Sagot :
To determine the possible values for [tex]\(n\)[/tex] in the context of a triangle with side lengths [tex]\(2x + 2\)[/tex] feet, [tex]\(x + 3\)[/tex] feet, and [tex]\(n\)[/tex] feet, we need to apply the triangle inequality theorem. The theorem states that the sum of the lengths of any two sides of a triangle must be greater than the length of the third side. Therefore, we have to satisfy the following three inequalities:
1. [tex]\( (2x + 2) + (x + 3) > n \)[/tex]
2. [tex]\( (2x + 2) + n > (x + 3) \)[/tex]
3. [tex]\( (x + 3) + n > (2x + 2) \)[/tex]
First, let's simplify each inequality step by step.
### Inequality 1:
[tex]\[ (2x + 2) + (x + 3) > n \][/tex]
[tex]\[ 2x + x + 2 + 3 > n \][/tex]
[tex]\[ 3x + 5 > n \][/tex]
[tex]\[ n < 3x + 5 \][/tex]
### Inequality 2:
[tex]\[ (2x + 2) + n > (x + 3) \][/tex]
[tex]\[ 2x + 2 + n > x + 3 \][/tex]
[tex]\[ 2x + n + 2 > x + 3 \][/tex]
Subtract [tex]\(x\)[/tex] from both sides:
[tex]\[ x + n + 2 > 3 \][/tex]
Subtract 2 from both sides:
[tex]\[ n > x + 1 \][/tex]
### Inequality 3:
[tex]\[ (x + 3) + n > (2x + 2) \][/tex]
[tex]\[ x + 3 + n > 2x + 2 \][/tex]
Subtract [tex]\(2x\)[/tex] from both sides:
[tex]\[ x + n + 3 > 2 \][/tex]
[tex]\[ n + 3 > x + 2 \][/tex]
Subtract 3 from both sides:
[tex]\[ n > x - 1 \][/tex]
Now, let’s combine the results of the inequalities:
- From Inequality 1: [tex]\(n < 3x + 5\)[/tex]
- From Inequality 2: [tex]\(n > x + 1\)[/tex]
- From Inequality 3: [tex]\(n > x - 1\)[/tex]
We need to take the most restrictive lower bound and the least restrictive upper bound:
- The lower bound is [tex]\(n > x - 1\)[/tex]
- The upper bound is [tex]\(n < 3x + 5\)[/tex]
Therefore, the expression representing the possible values of [tex]\(n\)[/tex] in feet is:
[tex]\[ x - 1 < n < 3x + 5 \][/tex]
So, the correct answer is:
[tex]\[ x - 1 < n < 3x + 5 \][/tex]
1. [tex]\( (2x + 2) + (x + 3) > n \)[/tex]
2. [tex]\( (2x + 2) + n > (x + 3) \)[/tex]
3. [tex]\( (x + 3) + n > (2x + 2) \)[/tex]
First, let's simplify each inequality step by step.
### Inequality 1:
[tex]\[ (2x + 2) + (x + 3) > n \][/tex]
[tex]\[ 2x + x + 2 + 3 > n \][/tex]
[tex]\[ 3x + 5 > n \][/tex]
[tex]\[ n < 3x + 5 \][/tex]
### Inequality 2:
[tex]\[ (2x + 2) + n > (x + 3) \][/tex]
[tex]\[ 2x + 2 + n > x + 3 \][/tex]
[tex]\[ 2x + n + 2 > x + 3 \][/tex]
Subtract [tex]\(x\)[/tex] from both sides:
[tex]\[ x + n + 2 > 3 \][/tex]
Subtract 2 from both sides:
[tex]\[ n > x + 1 \][/tex]
### Inequality 3:
[tex]\[ (x + 3) + n > (2x + 2) \][/tex]
[tex]\[ x + 3 + n > 2x + 2 \][/tex]
Subtract [tex]\(2x\)[/tex] from both sides:
[tex]\[ x + n + 3 > 2 \][/tex]
[tex]\[ n + 3 > x + 2 \][/tex]
Subtract 3 from both sides:
[tex]\[ n > x - 1 \][/tex]
Now, let’s combine the results of the inequalities:
- From Inequality 1: [tex]\(n < 3x + 5\)[/tex]
- From Inequality 2: [tex]\(n > x + 1\)[/tex]
- From Inequality 3: [tex]\(n > x - 1\)[/tex]
We need to take the most restrictive lower bound and the least restrictive upper bound:
- The lower bound is [tex]\(n > x - 1\)[/tex]
- The upper bound is [tex]\(n < 3x + 5\)[/tex]
Therefore, the expression representing the possible values of [tex]\(n\)[/tex] in feet is:
[tex]\[ x - 1 < n < 3x + 5 \][/tex]
So, the correct answer is:
[tex]\[ x - 1 < n < 3x + 5 \][/tex]
Thanks for using our platform. We aim to provide accurate and up-to-date answers to all your queries. Come back soon. We hope you found what you were looking for. Feel free to revisit us for more answers and updated information. Thank you for choosing Westonci.ca as your information source. We look forward to your next visit.