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Sagot :
To solve for the radius [tex]\( r \)[/tex] of the circle, we can use the relationship between the arc length [tex]\( s \)[/tex], the radius [tex]\( r \)[/tex], and the central angle [tex]\( \theta \)[/tex] (in radians). The formula that relates these quantities is:
[tex]\[ s = r \theta \][/tex]
We are given:
[tex]\[ \theta = \frac{\pi}{18} \quad \text{and} \quad s = \frac{5\pi}{6} \][/tex]
Our task is to find the radius [tex]\( r \)[/tex]. We can rearrange the formula to solve for [tex]\( r \)[/tex]:
[tex]\[ r = \frac{s}{\theta} \][/tex]
Substitute the given values into the equation:
[tex]\[ r = \frac{\frac{5\pi}{6}}{\frac{\pi}{18}} \][/tex]
To simplify the division of fractions, we multiply by the reciprocal:
[tex]\[ r = \frac{5\pi}{6} \cdot \frac{18}{\pi} \][/tex]
Notice that the [tex]\( \pi \)[/tex] terms in the numerator and denominator cancel each other out:
[tex]\[ r = \frac{5 \cdot 18}{6} \][/tex]
Further simplify the expression by performing the multiplication and division:
[tex]\[ r = \frac{90}{6} \][/tex]
[tex]\[ r = 15 \][/tex]
Therefore, the exact length of the radius is:
[tex]\[ r = 15 \, \text{m} \][/tex]
[tex]\[ s = r \theta \][/tex]
We are given:
[tex]\[ \theta = \frac{\pi}{18} \quad \text{and} \quad s = \frac{5\pi}{6} \][/tex]
Our task is to find the radius [tex]\( r \)[/tex]. We can rearrange the formula to solve for [tex]\( r \)[/tex]:
[tex]\[ r = \frac{s}{\theta} \][/tex]
Substitute the given values into the equation:
[tex]\[ r = \frac{\frac{5\pi}{6}}{\frac{\pi}{18}} \][/tex]
To simplify the division of fractions, we multiply by the reciprocal:
[tex]\[ r = \frac{5\pi}{6} \cdot \frac{18}{\pi} \][/tex]
Notice that the [tex]\( \pi \)[/tex] terms in the numerator and denominator cancel each other out:
[tex]\[ r = \frac{5 \cdot 18}{6} \][/tex]
Further simplify the expression by performing the multiplication and division:
[tex]\[ r = \frac{90}{6} \][/tex]
[tex]\[ r = 15 \][/tex]
Therefore, the exact length of the radius is:
[tex]\[ r = 15 \, \text{m} \][/tex]
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