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Which best describes the accuracy of their solutions?

\begin{tabular}{|l|l|}
\hline
Holly's work & Tamar's work \\
\hline
[tex]$(40+42)^2=58^2$[/tex] & [tex]$42^2 + 40^2 = 58^2$[/tex] \\
[tex]$82^2=3,364$[/tex] & [tex]$1,764 + 1,600 = 3,364$[/tex] \\
[tex]$6,724 \neq 3,364$[/tex] & [tex]$3,364 = 3,364$[/tex] \\
The triangle is not a right triangle. & The triangle is a right triangle. \\
\hline
\end{tabular}

A. Holly is correct.
B. Tamar is correct.
C. Neither Holly nor Tamar is correct.
D. Both Holly and Tamar are correct.


Sagot :

Let's analyze the given work for both Holly and Tamar to determine the accuracy of their solutions.

### Holly's Work
Holly attempts to verify if:
[tex]\[ (40 + 42)^2 = 58^2 \][/tex]

Calculating both sides:
- On the left side of the equation:
[tex]\[ (40 + 42)^2 = 82^2 \][/tex]
[tex]\[ 82^2 = 82 \times 82 = 6,724 \][/tex]

- On the right side of the equation:
[tex]\[ 58^2 = 58 \times 58 = 3,364 \][/tex]

Since:
[tex]\[ 6,724 \neq 3,364 \][/tex]

Holly's conclusion should be:
[tex]\[ \text{The triangle is not a right triangle.} \][/tex]

### Tamar's Work
Tamar attempts to verify if:
[tex]\[ 42^2 + 40^2 = 58^2 \][/tex]

Calculating both sides:
- On the left side of the equation:
[tex]\[ 42^2 + 40^2 = 42 \times 42 + 40 \times 40 \][/tex]
[tex]\[ 42^2 = 1,764 \][/tex]
[tex]\[ 40^2 = 1,600 \][/tex]
[tex]\[ 42^2 + 40^2 = 1,764 + 1,600 = 3,364 \][/tex]

- On the right side of the equation:
[tex]\[ 58^2 = 58 \times 58 = 3,364 \][/tex]

Since:
[tex]\[ 3,364 = 3,364 \][/tex]

Tamar's conclusion should be:
[tex]\[ \text{The triangle is a right triangle.} \][/tex]

### Conclusion
Based on the calculations:
- Holly's method is incorrect because the equation she used does not hold true: [tex]\( (40 + 42)^2 \neq 58^2 \)[/tex].
- Tamar's method is correct because the equation she used holds true: [tex]\( 42^2 + 40^2 = 58^2 \)[/tex].

Hence, Tamar is correct.