Discover answers to your questions with Westonci.ca, the leading Q&A platform that connects you with knowledgeable experts. Connect with a community of experts ready to provide precise solutions to your questions quickly and accurately. Discover detailed answers to your questions from a wide network of experts on our comprehensive Q&A platform.
Sagot :
To find the value of the function [tex]\( f(x) = 2x^2 + 5\sqrt{x-2} \)[/tex] at [tex]\( x = 6 \)[/tex], we need to substitute [tex]\( x \)[/tex] with 6 in the function and follow these steps:
1. Substitute [tex]\( x = 6 \)[/tex] into the function:
[tex]\[ f(6) = 2(6)^2 + 5\sqrt{6-2} \][/tex]
2. Calculate [tex]\( 6^2 \)[/tex]:
[tex]\[ 6^2 = 36 \][/tex]
3. Multiply by 2:
[tex]\[ 2 \cdot 36 = 72 \][/tex]
4. Calculate the value inside the square root:
[tex]\[ 6 - 2 = 4 \][/tex]
5. Take the square root of 4:
[tex]\[ \sqrt{4} = 2 \][/tex]
6. Multiply by 5:
[tex]\[ 5 \cdot 2 = 10 \][/tex]
7. Add the results from step 3 and step 6:
[tex]\[ 72 + 10 = 82 \][/tex]
Therefore,
[tex]\[ f(6) = 82 \][/tex]
1. Substitute [tex]\( x = 6 \)[/tex] into the function:
[tex]\[ f(6) = 2(6)^2 + 5\sqrt{6-2} \][/tex]
2. Calculate [tex]\( 6^2 \)[/tex]:
[tex]\[ 6^2 = 36 \][/tex]
3. Multiply by 2:
[tex]\[ 2 \cdot 36 = 72 \][/tex]
4. Calculate the value inside the square root:
[tex]\[ 6 - 2 = 4 \][/tex]
5. Take the square root of 4:
[tex]\[ \sqrt{4} = 2 \][/tex]
6. Multiply by 5:
[tex]\[ 5 \cdot 2 = 10 \][/tex]
7. Add the results from step 3 and step 6:
[tex]\[ 72 + 10 = 82 \][/tex]
Therefore,
[tex]\[ f(6) = 82 \][/tex]
Thanks for stopping by. We strive to provide the best answers for all your questions. See you again soon. We hope you found what you were looking for. Feel free to revisit us for more answers and updated information. We're glad you visited Westonci.ca. Return anytime for updated answers from our knowledgeable team.