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The variable [tex]\(v\)[/tex] varies inversely as the cube of [tex]\(w\)[/tex]. When [tex]\(w=6\)[/tex], [tex]\(v=36\)[/tex]. Marta's work finding [tex]\(v\)[/tex] when [tex]\(w=4\)[/tex] is shown.

[tex]\[
\begin{aligned}
v w^3 & =k \\
(36)(6)^3 & =v(4)^3 \\
(36)(216) & =v(64) \\
7,776 & =64v \\
121.5 & =v
\end{aligned}
\][/tex]

What is the first error, if any, in Marta's work?

A. She used an equation that models direct variation instead of inverse variation.
B. She solved an equation for [tex]\(v\)[/tex] without finding [tex]\(k\)[/tex] first.
C. She made an error when substituting 4, 6, and 36 into the equation.
D. There are no errors in Marta's work.


Sagot :

To address the question, let's go through Marta's steps to find the value of [tex]\( v \)[/tex] when [tex]\( w = 4 \)[/tex], given [tex]\( v \)[/tex] varies inversely as the cube of [tex]\( w \)[/tex], and [tex]\( w = 6 \)[/tex] and [tex]\( v = 36 \)[/tex]:

Step-by-Step Solution:

1. Understanding the Relationship:
Since [tex]\( v \)[/tex] varies inversely as the cube of [tex]\( w \)[/tex], we can express this relationship with the equation:
[tex]\[ v \cdot w^3 = k \][/tex]
where [tex]\( k \)[/tex] is a constant.

2. Finding the Constant [tex]\( k \)[/tex]:
We use the given values [tex]\( w = 6 \)[/tex] and [tex]\( v = 36 \)[/tex] to find [tex]\( k \)[/tex].
[tex]\[ 36 \cdot 6^3 = k \][/tex]
Simplifying this:
[tex]\[ 36 \cdot 216 = k \][/tex]
[tex]\[ k = 7776 \][/tex]

3. Finding [tex]\( v \)[/tex] when [tex]\( w = 4 \)[/tex]:
Using the constant [tex]\( k \)[/tex] we found, we substitute [tex]\( w = 4 \)[/tex] into the original equation to find [tex]\( v \)[/tex].
[tex]\[ v \cdot 4^3 = 7776 \][/tex]
Simplifying this:
[tex]\[ v \cdot 64 = 7776 \][/tex]
Solving for [tex]\( v \)[/tex]:
[tex]\[ v = \frac{7776}{64} \][/tex]
[tex]\[ v = 121.5 \][/tex]

Assessment of Marta's Steps:

Marta's steps showed the following:

1. [tex]\( v \cdot w^3 = k \)[/tex], correct.
2. [tex]\( (36)(6^3) = v(4^3) \)[/tex], correct.
3. [tex]\( (36)(216) = v(64) \)[/tex], correct.
4. [tex]\( 7776 = 64v \)[/tex], correct.
5. [tex]\( 121.5 = v \)[/tex], correct.

Since all of Marta's steps are correct and consistent with the inverse variation relationship and calculations, we can conclude that:

There are no errors in Marta's work.
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