Discover the answers to your questions at Westonci.ca, where experts share their knowledge and insights with you. Discover the answers you need from a community of experts ready to help you with their knowledge and experience in various fields. Get detailed and accurate answers to your questions from a dedicated community of experts on our Q&A platform.
Sagot :
Alright, let's determine which ordered pairs are in the solution set of the given system of linear inequalities.
The system of inequalities is:
1. [tex]\( y \geq -\frac{1}{2}x \)[/tex]
2. [tex]\( y < \frac{1}{2}x + 1 \)[/tex]
We will evaluate each ordered pair given in the four groups to see if it satisfies both inequalities. Let's take them one by one.
### Group 1:
[tex]\((5, -2), (3, 1), (-4, 2)\)[/tex]
#### For [tex]\((5, -2)\)[/tex]:
- Check [tex]\( y \geq -\frac{1}{2}x \)[/tex]:
[tex]\[ -2 \geq -\frac{1}{2} \times 5 \][/tex]
[tex]\[ -2 \geq -2.5 \][/tex] (True)
- Check [tex]\( y < \frac{1}{2}x + 1 \)[/tex]:
[tex]\[ -2 < \frac{1}{2} \times 5 + 1 \][/tex]
[tex]\[ -2 < 3.5 \][/tex] (True)
#### For [tex]\((3, 1)\)[/tex]:
- Check [tex]\( y \geq -\frac{1}{2}x \)[/tex]:
[tex]\[ 1 \geq -\frac{1}{2} \times 3 \][/tex]
[tex]\[ 1 \geq -1.5 \][/tex] (True)
- Check [tex]\( y < \frac{1}{2}x + 1 \)[/tex]:
[tex]\[ 1 < \frac{1}{2} \times 3 + 1 \][/tex]
[tex]\[ 1 < 2.5 \][/tex] (True)
#### For [tex]\((-4, 2)\)[/tex]:
- Check [tex]\( y \geq -\frac{1}{2}x \)[/tex]:
[tex]\[ 2 \geq -\frac{1}{2} \times -4 \][/tex]
[tex]\[ 2 \geq 2 \][/tex] (True)
- Check [tex]\( y < \frac{1}{2}x + 1 \)[/tex]:
[tex]\[ 2 < \frac{1}{2} \times -4 + 1 \][/tex]
[tex]\[ 2 < -1 + 1 \][/tex]
[tex]\[ 2 < 0 \][/tex] (False)
### Conclusion for Group 1:
The pair [tex]\((-4, 2)\)[/tex] does not satisfy both inequalities.
### Group 2:
[tex]\((5, -2), (3, -1), (4, -3)\)[/tex]
#### For [tex]\((5, -2)\)[/tex]:
- As before: (True, True)
#### For [tex]\((3, -1)\)[/tex]:
- Check [tex]\( y \geq -\frac{1}{2}x \)[/tex]:
[tex]\[ -1 \geq -\frac{1}{2} \times 3 \][/tex]
[tex]\[ -1 \geq -1.5 \][/tex] (True)
- Check [tex]\( y < \frac{1}{2}x + 1 \)[/tex]:
[tex]\[ -1 < \frac{1}{2} \times 3 + 1 \][/tex]
[tex]\[ -1 < 2.5 \][/tex] (True)
#### For [tex]\((4, -3)\)[/tex]:
- Check [tex]\( y \geq -\frac{1}{2}x \)[/tex]:
[tex]\[ -3 \geq -\frac{1}{2} \times 4 \][/tex]
[tex]\[ -3 \geq -2 \][/tex] (False)
- Check [tex]\( y < \frac{1}{2}x + 1 \)[/tex]:
[tex]\[ -3 < \frac{1}{2} \times 4 + 1 \][/tex]
[tex]\[ -3 < 3 \][/tex] (True)
### Conclusion for Group 2:
The pair [tex]\((4, -3)\)[/tex] does not satisfy the first inequality.
### Group 3:
[tex]\((5, -2), (3, 1), (4, 2)\)[/tex]
#### For [tex]\((5, -2)\)[/tex]:
- As before: (True, True)
#### For [tex]\((3, 1)\)[/tex]:
- As before: (True, True)
#### For [tex]\((4, 2)\)[/tex]:
- Check [tex]\( y \geq -\frac{1}{2}x \)[/tex]:
[tex]\[ 2 \geq -\frac{1}{2} \times 4 \][/tex]
[tex]\[ 2 \geq -2 \][/tex] (True)
- Check [tex]\( y < \frac{1}{2}x + 1 \)[/tex]:
[tex]\[ 2 < \frac{1}{2} \times 4 + 1 \][/tex]
[tex]\[ 2 < 3 \][/tex] (True)
### Conclusion for Group 3:
All pairs satisfy both inequalities.
### Group 4:
[tex]\((5, -2), (-3, 1), (4, 2)\)[/tex]
#### For [tex]\((5, -2)\)[/tex]:
- As before: (True, True)
#### For [tex]\((-3, 1)\)[/tex]:
- Check [tex]\( y \geq -\frac{1}{2}x \)[/tex]:
[tex]\[ 1 \geq -\frac{1}{2} \times -3 \][/tex]
[tex]\[ 1 \geq 1.5 \][/tex] (False)
- Check [tex]\( y < \frac{1}{2}x + 1 \)[/tex]:
[tex]\[ 1 < \frac{1}{2} \times -3 + 1 \][/tex]
[tex]\[ 1 < -1.5 + 1 \][/tex]
[tex]\[ 1 < -0.5 \][/tex] (False)
#### For [tex]\((4, 2)\)[/tex]:
- As before: (True, True)
### Conclusion for Group 4:
The pair [tex]\((-3, 1)\)[/tex] does not satisfy either inequality.
### Final Conclusion:
The group where all ordered pairs satisfy both inequalities is Group 3:
[tex]\((5, -2), (3, 1), (4, 2)\)[/tex].
The system of inequalities is:
1. [tex]\( y \geq -\frac{1}{2}x \)[/tex]
2. [tex]\( y < \frac{1}{2}x + 1 \)[/tex]
We will evaluate each ordered pair given in the four groups to see if it satisfies both inequalities. Let's take them one by one.
### Group 1:
[tex]\((5, -2), (3, 1), (-4, 2)\)[/tex]
#### For [tex]\((5, -2)\)[/tex]:
- Check [tex]\( y \geq -\frac{1}{2}x \)[/tex]:
[tex]\[ -2 \geq -\frac{1}{2} \times 5 \][/tex]
[tex]\[ -2 \geq -2.5 \][/tex] (True)
- Check [tex]\( y < \frac{1}{2}x + 1 \)[/tex]:
[tex]\[ -2 < \frac{1}{2} \times 5 + 1 \][/tex]
[tex]\[ -2 < 3.5 \][/tex] (True)
#### For [tex]\((3, 1)\)[/tex]:
- Check [tex]\( y \geq -\frac{1}{2}x \)[/tex]:
[tex]\[ 1 \geq -\frac{1}{2} \times 3 \][/tex]
[tex]\[ 1 \geq -1.5 \][/tex] (True)
- Check [tex]\( y < \frac{1}{2}x + 1 \)[/tex]:
[tex]\[ 1 < \frac{1}{2} \times 3 + 1 \][/tex]
[tex]\[ 1 < 2.5 \][/tex] (True)
#### For [tex]\((-4, 2)\)[/tex]:
- Check [tex]\( y \geq -\frac{1}{2}x \)[/tex]:
[tex]\[ 2 \geq -\frac{1}{2} \times -4 \][/tex]
[tex]\[ 2 \geq 2 \][/tex] (True)
- Check [tex]\( y < \frac{1}{2}x + 1 \)[/tex]:
[tex]\[ 2 < \frac{1}{2} \times -4 + 1 \][/tex]
[tex]\[ 2 < -1 + 1 \][/tex]
[tex]\[ 2 < 0 \][/tex] (False)
### Conclusion for Group 1:
The pair [tex]\((-4, 2)\)[/tex] does not satisfy both inequalities.
### Group 2:
[tex]\((5, -2), (3, -1), (4, -3)\)[/tex]
#### For [tex]\((5, -2)\)[/tex]:
- As before: (True, True)
#### For [tex]\((3, -1)\)[/tex]:
- Check [tex]\( y \geq -\frac{1}{2}x \)[/tex]:
[tex]\[ -1 \geq -\frac{1}{2} \times 3 \][/tex]
[tex]\[ -1 \geq -1.5 \][/tex] (True)
- Check [tex]\( y < \frac{1}{2}x + 1 \)[/tex]:
[tex]\[ -1 < \frac{1}{2} \times 3 + 1 \][/tex]
[tex]\[ -1 < 2.5 \][/tex] (True)
#### For [tex]\((4, -3)\)[/tex]:
- Check [tex]\( y \geq -\frac{1}{2}x \)[/tex]:
[tex]\[ -3 \geq -\frac{1}{2} \times 4 \][/tex]
[tex]\[ -3 \geq -2 \][/tex] (False)
- Check [tex]\( y < \frac{1}{2}x + 1 \)[/tex]:
[tex]\[ -3 < \frac{1}{2} \times 4 + 1 \][/tex]
[tex]\[ -3 < 3 \][/tex] (True)
### Conclusion for Group 2:
The pair [tex]\((4, -3)\)[/tex] does not satisfy the first inequality.
### Group 3:
[tex]\((5, -2), (3, 1), (4, 2)\)[/tex]
#### For [tex]\((5, -2)\)[/tex]:
- As before: (True, True)
#### For [tex]\((3, 1)\)[/tex]:
- As before: (True, True)
#### For [tex]\((4, 2)\)[/tex]:
- Check [tex]\( y \geq -\frac{1}{2}x \)[/tex]:
[tex]\[ 2 \geq -\frac{1}{2} \times 4 \][/tex]
[tex]\[ 2 \geq -2 \][/tex] (True)
- Check [tex]\( y < \frac{1}{2}x + 1 \)[/tex]:
[tex]\[ 2 < \frac{1}{2} \times 4 + 1 \][/tex]
[tex]\[ 2 < 3 \][/tex] (True)
### Conclusion for Group 3:
All pairs satisfy both inequalities.
### Group 4:
[tex]\((5, -2), (-3, 1), (4, 2)\)[/tex]
#### For [tex]\((5, -2)\)[/tex]:
- As before: (True, True)
#### For [tex]\((-3, 1)\)[/tex]:
- Check [tex]\( y \geq -\frac{1}{2}x \)[/tex]:
[tex]\[ 1 \geq -\frac{1}{2} \times -3 \][/tex]
[tex]\[ 1 \geq 1.5 \][/tex] (False)
- Check [tex]\( y < \frac{1}{2}x + 1 \)[/tex]:
[tex]\[ 1 < \frac{1}{2} \times -3 + 1 \][/tex]
[tex]\[ 1 < -1.5 + 1 \][/tex]
[tex]\[ 1 < -0.5 \][/tex] (False)
#### For [tex]\((4, 2)\)[/tex]:
- As before: (True, True)
### Conclusion for Group 4:
The pair [tex]\((-3, 1)\)[/tex] does not satisfy either inequality.
### Final Conclusion:
The group where all ordered pairs satisfy both inequalities is Group 3:
[tex]\((5, -2), (3, 1), (4, 2)\)[/tex].
We hope this information was helpful. Feel free to return anytime for more answers to your questions and concerns. Thank you for choosing our platform. We're dedicated to providing the best answers for all your questions. Visit us again. Westonci.ca is your go-to source for reliable answers. Return soon for more expert insights.