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What would the ratio of phenotypes be for the offspring of two heterozygous yellow plants [tex](Yy)[/tex]?

Enter the genotype ratio and the phenotype ratio.

[tex]\[
\begin{array}{|c|c|c|}
\hline
& Y & y \\
\hline
Y & YY & Yy \\
\hline
y & Yy & yy \\
\hline
\end{array}
\][/tex]

Genotype Ratio (YY : Yy : yy):
[tex]\[
\square : \square : \square
\][/tex]

[tex]\[
\begin{array}{|l|l|}
\hline
Y - \text{yellow} & y - \text{green} \\
\hline
R - \text{round} & r - \text{wrinkled} \\
\hline
A - \text{purple} & a - \text{white} \\
\hline
\begin{array}{l}
\text{Remember, capital letters denote} \\
\text{dominant alleles.}
\end{array} \\
\hline
\end{array}
\][/tex]

Phenotype Ratio (Yellow : Green):
[tex]\[
\square : \square
\][/tex]

Sagot :

GinnyAnswer
To determine the genotype and phenotype ratios for the offspring of two heterozygous yellow plants (Yy), we can use a Punnett square as follows:

We start by setting up the Punnett square:

[tex]\[ \begin{array}{|c|c|c|} \hline & Y & y \\ \hline Y & YY & Yy \\ \hline y & Yy & yy \\ \hline \end{array} \][/tex]

Here's what we get inside the Punnett square:
- YY (Yellow)
- Yy (Yellow)
- Yy (Yellow)
- yy (Green)

From the Punnett square, we can count the occurrence of each genotype:
- YY: 1
- Yy: 2
- yy: 1

Thus, the genotype ratio [tex]\( \text{(YY:Yy:yy)} \)[/tex] is:
[tex]\[ 1 : 2 : 1 \][/tex]

Next, we look at the phenotype ratio. Yellow is the dominant phenotype, and will manifest in both YY and Yy genotypes. Green is the recessive phenotype and will manifest only in the yy genotype.

Counting the phenotypes from our genotype results:
- Yellow (from YY and Yy): 3
- Green (from yy): 1

So, the phenotype ratio [tex]\( \text{(Yellow:Green)} \)[/tex] is:
[tex]\[ 3 : 1 \][/tex]

Summary:

Genotype Ratio (YY:Yy:yy):
[tex]\[ 1 : 2 : 1 \][/tex]

Phenotype Ratio (Yellow:Green):
[tex]\[ 3 : 1 \][/tex]
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