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How many moles of [tex][tex]$Ba\left(NO_3\right)_2$[/tex][/tex] are there in [tex]0.25 \, L[/tex] of a [tex]2.00 \, M \, Ba\left(NO_3\right)_2[/tex] solution?

Use [tex]\text{molarity} = \frac{\text{moles of solute}}{\text{liters of solution}}[/tex].

A. [tex]0.13 \, mol[/tex]
B. [tex]0.50 \, mol[/tex]
C. [tex]2.25 \, mol[/tex]
D. [tex]8.0 \, mol[/tex]


Sagot :

To determine how many moles of [tex]\( \text{Ba}(NO_3)_2 \)[/tex] are present in 0.25 liters of a 2.00 M [tex]\( \text{Ba}(NO_3)_2 \)[/tex] solution, we can use the formula for molarity:

[tex]\[ \text{Molarity} = \frac{\text{moles of solute}}{\text{liters of solution}} \][/tex]

We are given:
- Volume of the solution, [tex]\( V = 0.25 \, \text{L} \)[/tex]
- Molarity of the solution, [tex]\( M = 2.00 \, \text{M} \)[/tex]

We need to find the moles of solute ([tex]\( \text{Ba}(NO_3)_2 \)[/tex]), which can be calculated by rearranging the formula to:

[tex]\[ \text{moles of solute} = \text{Molarity} \times \text{liters of solution} \][/tex]

Substituting the given values:

[tex]\[ \text{moles of solute} = 2.00 \, \text{M} \times 0.25 \, \text{L} \][/tex]

[tex]\[ \text{moles of solute} = 0.50 \, \text{mol} \][/tex]

So, there are 0.50 moles of [tex]\( \text{Ba}(NO_3)_2 \)[/tex] in the 0.25 liters of the 2.00 M solution.

The correct answer is [tex]\( 0.50 \, \text{mol} \)[/tex].