At Westonci.ca, we make it easy to get the answers you need from a community of informed and experienced contributors. Connect with a community of experts ready to help you find accurate solutions to your questions quickly and efficiently. Join our Q&A platform to connect with experts dedicated to providing accurate answers to your questions in various fields.
Sagot :
To determine which equation correctly describes how to calculate the mass of an object given its acceleration and the net force acting on it, let's start with Newton's second law of motion.
According to Newton's second law of motion, the force [tex]\( F \)[/tex] acting on an object is the product of its mass [tex]\( m \)[/tex] and its acceleration [tex]\( a \)[/tex]. This relationship is mathematically represented as:
[tex]\[ F = m \cdot a \][/tex]
We need to find an equation that isolates the mass [tex]\( m \)[/tex]. To do this, we rearrange the equation to solve for [tex]\( m \)[/tex]. We divide both sides of the equation by the acceleration [tex]\( a \)[/tex]:
[tex]\[ m = \frac{F}{a} \][/tex]
This equation tells us that the mass of an object is equal to the net force acting on it divided by its acceleration.
Now let's examine the given options:
A. [tex]\( m = F^{\circ} \)[/tex]
This option is not correct; [tex]\( F^{\circ} \)[/tex] does not relate to the equation [tex]\( F = m \cdot a \)[/tex].
B. [tex]\( m = \frac{a}{F} \)[/tex]
This option is incorrect because it suggests that the mass is the acceleration divided by the force, which contradicts [tex]\( m = \frac{F}{a} \)[/tex].
C. [tex]\( m = \frac{F}{a} \)[/tex]
This option is correct. It matches the equation we derived from Newton's second law, showing that the mass is the net force divided by the acceleration.
D. [tex]\( m = F \cdot a \)[/tex]
This option is incorrect because it suggests that the mass is the product of the force and the acceleration, which does not match Newton's second law.
Therefore, the correct equation showing how to calculate the mass of an object given its acceleration and the net force acting on it is:
[tex]\[ \boxed{m = \frac{F}{a}} \][/tex]
Thus, the correct answer is option C.
According to Newton's second law of motion, the force [tex]\( F \)[/tex] acting on an object is the product of its mass [tex]\( m \)[/tex] and its acceleration [tex]\( a \)[/tex]. This relationship is mathematically represented as:
[tex]\[ F = m \cdot a \][/tex]
We need to find an equation that isolates the mass [tex]\( m \)[/tex]. To do this, we rearrange the equation to solve for [tex]\( m \)[/tex]. We divide both sides of the equation by the acceleration [tex]\( a \)[/tex]:
[tex]\[ m = \frac{F}{a} \][/tex]
This equation tells us that the mass of an object is equal to the net force acting on it divided by its acceleration.
Now let's examine the given options:
A. [tex]\( m = F^{\circ} \)[/tex]
This option is not correct; [tex]\( F^{\circ} \)[/tex] does not relate to the equation [tex]\( F = m \cdot a \)[/tex].
B. [tex]\( m = \frac{a}{F} \)[/tex]
This option is incorrect because it suggests that the mass is the acceleration divided by the force, which contradicts [tex]\( m = \frac{F}{a} \)[/tex].
C. [tex]\( m = \frac{F}{a} \)[/tex]
This option is correct. It matches the equation we derived from Newton's second law, showing that the mass is the net force divided by the acceleration.
D. [tex]\( m = F \cdot a \)[/tex]
This option is incorrect because it suggests that the mass is the product of the force and the acceleration, which does not match Newton's second law.
Therefore, the correct equation showing how to calculate the mass of an object given its acceleration and the net force acting on it is:
[tex]\[ \boxed{m = \frac{F}{a}} \][/tex]
Thus, the correct answer is option C.
We appreciate your visit. Hopefully, the answers you found were beneficial. Don't hesitate to come back for more information. Thank you for choosing our platform. We're dedicated to providing the best answers for all your questions. Visit us again. Keep exploring Westonci.ca for more insightful answers to your questions. We're here to help.