Welcome to Westonci.ca, where curiosity meets expertise. Ask any question and receive fast, accurate answers from our knowledgeable community. Explore thousands of questions and answers from knowledgeable experts in various fields on our Q&A platform. Get quick and reliable solutions to your questions from a community of experienced experts on our platform.

Factorize completely:

a) [tex]24x^2 + 6xy[/tex]


Sagot :

To factorize the given expression [tex]\(24 x^2 + 6 x y\)[/tex] completely, follow these steps:

1. Identify the Greatest Common Factor (GCF):
Start by identifying the greatest common factor of all terms in the polynomial.

The terms are [tex]\(24 x^2\)[/tex] and [tex]\(6 x y\)[/tex]. The numerical coefficients are 24 and 6, and the highest common factor of these numbers is 6. Both terms also share a common variable, [tex]\(x\)[/tex].

So, the GCF of [tex]\(24 x^2\)[/tex] and [tex]\(6 x y\)[/tex] is [tex]\(6x\)[/tex].

2. Factor out the GCF:
Now, divide each term by the GCF [tex]\(6x\)[/tex]:

[tex]\[ = 24 x^2 \div 6x + 6 x y \div 6x \][/tex]

Simplifying each term:

[tex]\[ = 4x + y \][/tex]

Therefore, when the GCF [tex]\(6x\)[/tex] is factored out from the original expression, it becomes:

[tex]\[ 24 x^2 + 6 x y = 6x(4x + y) \][/tex]

So, the completely factorized form of the expression [tex]\(24 x^2 + 6 x y\)[/tex] is:

[tex]\[ \boxed{6x(4x + y)} \][/tex]