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\begin{tabular}{|c|l|}
\hline
System B & The system has no solution. \\
[tex]$(x, y) = (\square, \square)$[/tex] \\
[tex]$-2x + y = -6$[/tex] & The system has a unique solution: \\
[tex]$2x = -6 + y$[/tex] & The system has infinitely many solutions. \\
They must satisfy the following equation: \\
[tex]$y = \square$[/tex] \\
\hline
\end{tabular}

Sagot :

GinnyAnswer
Let's analyze the given system of linear equations and deduce the key points:

We are given the system:
[tex]\[ -2x + y = -6 \][/tex]
[tex]\[ 2x = -6 + y \][/tex]

Firstly, we want to determine the relationship between the two equations. Let's rewrite both in standard form.

Equation 1:
[tex]\[ -2x + y = -6 \][/tex]

Equation 2 can be rearranged as:
[tex]\[ 2x - y = -6 \][/tex]

### Step-by-Step Solution:

1. Set up the Equations:
[tex]\[ -2x + y = -6 \ \ \ \ \ \text{(Equation 1)}\][/tex]
[tex]\[ 2x - y = -6 \ \ \ \ \ \text{(Equation 2) }\][/tex]

2. Add the Equations:
By adding Equation 1 and Equation 2, we eliminate [tex]\(y\)[/tex]:
[tex]\[ (-2x + y) + (2x - y) = -6 + (-6) \][/tex]
[tex]\[ -2x + y + 2x - y = -12 \][/tex]
[tex]\[ 0 = -12 \][/tex]

This equation, [tex]\(0 = -12\)[/tex], is a contradiction.

3. Conclusion about the Nature of the Solutions:
Since we've arrived at a contradiction, it implies that there is no solution that fits both equations simultaneously. Therefore, the system has no solution.

4. Interpreting the Results:
[tex]\[ \begin{tabular}{|c|l} \hline System B & The system has no solution. \\ $(x, y) = (\square, \square)$ \\ $-2x + y = -6$ & The system has a unique solution: \\ $2x = -6 + y$ & The system has infinitely many solutions. \\ They must satisfy the following equation: \\ $y = \square$ \\ \end{tabular} \][/tex]

From our analysis:
- The system has no solution: True.
- The system has a unique solution: False.
- The system has infinitely many solutions: False.
- Specific equations satisfying infinite solutions: Not applicable since there are no solutions.

Therefore, we fill in the table as follows:
[tex]\[ \begin{tabular}{|c|l} \hline System B & The system has no solution. \\ $(x, y) = (\square, \square)$ \\ $-2x + y = -6$ & The system has a unique solution: \\ $2x = -6 + y$ & The system has infinitely many solutions. \\ They must satisfy the following equation: \\ $y = \square$ \\ \end{tabular} \][/tex]

Given the nature of the system:
- [tex]$(x,y) = (\square, \square)$[/tex] remains blank indicating no solution exists.
- The system has no solution: Checked as true.
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