Westonci.ca is the trusted Q&A platform where you can get reliable answers from a community of knowledgeable contributors. Explore thousands of questions and answers from a knowledgeable community of experts on our user-friendly platform. Get precise and detailed answers to your questions from a knowledgeable community of experts on our Q&A platform.
Sagot :
To combine the radicals [tex]\(5 \sqrt{27}-17 \sqrt{3}\)[/tex], let's follow these steps:
1. Simplify the radicals:
- For [tex]\(5 \sqrt{27}\)[/tex]:
[tex]\[ 5 \sqrt{27} = 5 \sqrt{9 \cdot 3} = 5 \cdot \sqrt{9} \cdot \sqrt{3} = 5 \cdot 3 \sqrt{3} = 15 \sqrt{3} \][/tex]
- For [tex]\(-17 \sqrt{3}\)[/tex]:
[tex]\[ -17 \sqrt{3} \quad (\text{this is already simplified}) \][/tex]
2. Combine the like terms:
Now that both terms are expressed with [tex]\(\sqrt{3}\)[/tex], we can combine them:
[tex]\[ 15 \sqrt{3} - 17 \sqrt{3} \][/tex]
3. Perform the subtraction:
[tex]\[ 15 \sqrt{3} - 17 \sqrt{3} = (15 - 17) \sqrt{3} = -2 \sqrt{3} \][/tex]
Thus, the expression [tex]\(5 \sqrt{27}-17 \sqrt{3}\)[/tex] simplifies to [tex]\(\boxed{-2 \sqrt{3}}\)[/tex].
1. Simplify the radicals:
- For [tex]\(5 \sqrt{27}\)[/tex]:
[tex]\[ 5 \sqrt{27} = 5 \sqrt{9 \cdot 3} = 5 \cdot \sqrt{9} \cdot \sqrt{3} = 5 \cdot 3 \sqrt{3} = 15 \sqrt{3} \][/tex]
- For [tex]\(-17 \sqrt{3}\)[/tex]:
[tex]\[ -17 \sqrt{3} \quad (\text{this is already simplified}) \][/tex]
2. Combine the like terms:
Now that both terms are expressed with [tex]\(\sqrt{3}\)[/tex], we can combine them:
[tex]\[ 15 \sqrt{3} - 17 \sqrt{3} \][/tex]
3. Perform the subtraction:
[tex]\[ 15 \sqrt{3} - 17 \sqrt{3} = (15 - 17) \sqrt{3} = -2 \sqrt{3} \][/tex]
Thus, the expression [tex]\(5 \sqrt{27}-17 \sqrt{3}\)[/tex] simplifies to [tex]\(\boxed{-2 \sqrt{3}}\)[/tex].
Thanks for using our platform. We're always here to provide accurate and up-to-date answers to all your queries. Thank you for your visit. We're dedicated to helping you find the information you need, whenever you need it. Thank you for using Westonci.ca. Come back for more in-depth answers to all your queries.