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Sagot :
To find the midpoint of the line segment with endpoints [tex]\( G(10, 1) \)[/tex] and [tex]\( H(3, 5) \)[/tex], we use the midpoint formula. The midpoint formula for a line segment with endpoints [tex]\((x_1, y_1)\)[/tex] and [tex]\((x_2, y_2)\)[/tex] is:
[tex]\[ \left( \frac{x_1 + x_2}{2}, \frac{y_1 + y_2}{2} \right) \][/tex]
Here, we have the coordinates [tex]\( G(10, 1) \)[/tex] and [tex]\( H(3, 5) \)[/tex].
First, calculate the x-coordinate of the midpoint:
[tex]\[ x_{\text{midpoint}} = \frac{10 + 3}{2} = \frac{13}{2} \][/tex]
Next, calculate the y-coordinate of the midpoint:
[tex]\[ y_{\text{midpoint}} = \frac{1 + 5}{2} = 3 \][/tex]
Therefore, the midpoint of [tex]\(\overline{GH}\)[/tex] is:
[tex]\[ \left( \frac{13}{2}, 3 \right) \][/tex]
So, the correct answer is:
[tex]\[ \boxed{\left( \frac{13}{2}, 3 \right)} \][/tex]
[tex]\[ \left( \frac{x_1 + x_2}{2}, \frac{y_1 + y_2}{2} \right) \][/tex]
Here, we have the coordinates [tex]\( G(10, 1) \)[/tex] and [tex]\( H(3, 5) \)[/tex].
First, calculate the x-coordinate of the midpoint:
[tex]\[ x_{\text{midpoint}} = \frac{10 + 3}{2} = \frac{13}{2} \][/tex]
Next, calculate the y-coordinate of the midpoint:
[tex]\[ y_{\text{midpoint}} = \frac{1 + 5}{2} = 3 \][/tex]
Therefore, the midpoint of [tex]\(\overline{GH}\)[/tex] is:
[tex]\[ \left( \frac{13}{2}, 3 \right) \][/tex]
So, the correct answer is:
[tex]\[ \boxed{\left( \frac{13}{2}, 3 \right)} \][/tex]
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