Westonci.ca connects you with experts who provide insightful answers to your questions. Join us today and start learning! Our platform connects you with professionals ready to provide precise answers to all your questions in various areas of expertise. Get immediate and reliable solutions to your questions from a community of experienced professionals on our platform.

Find the mean for the data items in the given frequency distribution.

[tex]\[
\begin{tabular}{|l|l|l|l|l|l|l|l|l|}
\hline
Score, $x$ & 1 & 2 & 3 & 4 & 5 & 6 & 7 & 8 \\
\hline
Frequency, $f$ & 3 & 3 & 6 & 6 & 6 & 2 & 6 & 3 \\
\hline
\end{tabular}
\][/tex]

The mean is [tex]$\square$[/tex]. (Round to 3 decimal places as needed.)


Sagot :

To find the mean of the given frequency distribution, we follow these steps:

1. List the Scores and Frequencies:
[tex]\[ \begin{array}{|c|c|c|c|c|c|c|c|c|} \hline \text{Score, } x & 1 & 2 & 3 & 4 & 5 & 6 & 7 & 8 \\ \hline \text{Frequency, } f & 3 & 3 & 6 & 6 & 6 & 2 & 6 & 3 \\ \hline \end{array} \][/tex]

2. Calculate the Total Frequency:
To determine the total frequency, sum up all the frequencies:
[tex]\[ \text{Total Frequency} = 3 + 3 + 6 + 6 + 6 + 2 + 6 + 3 = 35 \][/tex]

3. Calculate the Weighted Sum of Scores:
Each score needs to be multiplied by its corresponding frequency, and then all these products should be summed:
[tex]\[ \text{Weighted Sum} = (1 \times 3) + (2 \times 3) + (3 \times 6) + (4 \times 6) + (5 \times 6) + (6 \times 2) + (7 \times 6) + (8 \times 3) \][/tex]
Calculating each individually:
[tex]\[ \begin{align*} 1 \times 3 & = 3 \\ 2 \times 3 & = 6 \\ 3 \times 6 & = 18 \\ 4 \times 6 & = 24 \\ 5 \times 6 & = 30 \\ 6 \times 2 & = 12 \\ 7 \times 6 & = 42 \\ 8 \times 3 & = 24 \\ \end{align*} \][/tex]
Summing these products:
[tex]\[ \text{Weighted Sum} = 3 + 6 + 18 + 24 + 30 + 12 + 42 + 24 = 159 \][/tex]

4. Calculate the Mean:
The mean ([tex]\(\bar{x}\)[/tex]) can be calculated by dividing the weighted sum by the total frequency:
[tex]\[ \bar{x} = \frac{\text{Weighted Sum}}{\text{Total Frequency}} = \frac{159}{35} \approx 4.543 \][/tex]

Therefore, the mean of the given frequency distribution is:
[tex]\[ \boxed{4.543} \][/tex]
Thank you for your visit. We're dedicated to helping you find the information you need, whenever you need it. Thank you for your visit. We're committed to providing you with the best information available. Return anytime for more. Westonci.ca is here to provide the answers you seek. Return often for more expert solutions.