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Rewrite the long division expression to make it clear:

[tex]\[
\begin{array}{r}
\phantom{8\ } \, 11238 \\
\overline{12 \, \big) \, 11238}
\end{array}
\][/tex]


Sagot :

Sure, let's divide 11238 by 8 step by step.

1. Divide the first digit (1) by 8:
- 1 is less than 8, so we cannot divide 1 by 8. Hence, we consider the first two digits: 11.

2. Divide 11 by 8:
- 8 can go into 11 once (8 1 = 8).
- Write 1 above the line as the first digit of the quotient.
- Subtract 8 from 11, which equals 3. The new dividend becomes 32 (by bringing down the next digit which is 2).

So far: Quotient = 1, Partial Remainder = 3

3. Divide 32 by 8:
- 8 can go into 32 four times (8
4 = 32).
- Write 4 above the line next to the 1 in the quotient.
- Subtract 32 from 32, which equals 0. The new dividend becomes 03 (by bringing down the next digit which is 3).

So far: Quotient = 14, Partial Remainder = 0

4. Divide 03 by 8:
- 3 is less than 8, so we cannot divide 3 by 8. Hence, we consider the first three digits: 03.
- Since 3 cannot be divided by 8, the quotient for this step is 0, and we bring down the next digit, which is 8. The new dividend becomes 38.

So far: Quotient = 140, Partial Remainder = 38

5. Divide 38 by 8:
- 8 can go into 38 four times (8 * 4 = 32).
- Write 4 above the line next to the 140 in the quotient.
- Subtract 32 from 38, which equals 6. There are no more digits to bring down.

So far: Quotient = 1404, Remainder = 6

After completing these steps, we find that the quotient of 11238 divided by 8 is 1404 with a remainder of 6. Therefore, the final answer is:

- Quotient = 1404
- Remainder = 6