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In a class, 32.1% of students have a brother B, 57.1% of students have a sister S, and 14.3% have
both a brother and a sister.
a. Determine the probability of S given B, to the nearest tenth of a percent.
b. The teacher wants to make a slide for her class that explains these results. What could he
write?


Sagot :

Answer:

a. 44.6%

b. "In this class, 32.1% of students have a brother, 57.1% have a sister, and 14.3% have both a brother and a sister. Therefore, the probability of a student having a sister given that they have a brother is approximately 44.6%."

Step-by-step explanation:

a. The probability of S given B is the probability of having a sister given that you have a brother. This is calculated by dividing the percentage of students who have both a brother and a sister (14.3%) by the percentage of students who have a brother (32.1%). This gives us a probability of approximately 44.6%.

b. The teacher could write on the slide: "In this class, 32.1% of students have a brother, 57.1% have a sister, and 14.3% have both a brother and a sister. Therefore, the probability of a student having a sister given that they have a brother is approximately 44.6%."