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Solve for [tex][tex]$z$[/tex][/tex].

[tex]
\begin{array}{c}
\frac{8z + 4}{-4} = -9 \\
z = \, ?
\end{array}
[/tex]

Sagot :

GinnyAnswer
To solve for [tex]\( z \)[/tex] in the equation [tex]\(\frac{8z + 4}{-4} = -9\)[/tex], follow these steps:

1. Clear the Denominator: Multiply both sides of the equation by [tex]\(-4\)[/tex] to eliminate the denominator.
[tex]\[ \frac{8z + 4}{-4} \cdot (-4) = -9 \cdot (-4) \][/tex]
Simplifying this gives:
[tex]\[ 8z + 4 = 36 \][/tex]

2. Isolate the Term with [tex]\( z \)[/tex]: Subtract 4 from both sides to isolate the [tex]\( 8z \)[/tex] term.
[tex]\[ 8z + 4 - 4 = 36 - 4 \][/tex]
Simplifying this gives:
[tex]\[ 8z = 32 \][/tex]

3. Solve for [tex]\( z \)[/tex]: Divide both sides by 8 to solve for [tex]\( z \)[/tex].
[tex]\[ \frac{8z}{8} = \frac{32}{8} \][/tex]
Simplifying this gives:
[tex]\[ z = 4 \][/tex]

Thus, the solution to the equation [tex]\(\frac{8z + 4}{-4} = -9\)[/tex] is:
[tex]\[ z = 4 \][/tex]
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