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5. ¿En cuál de los siguientes procedimientos se resuelven sin error las siguientes operaciones?

[tex]$
\frac{(8)(-7)(6)}{(-4)(-2)(-3)}=
$[/tex]

A) [tex]$\frac{(8)(-7)(6)}{(-4)(-2)(-3)}=\frac{-336}{-24}=-14$[/tex]

B) [tex]$\frac{(8)(-7)(6)}{(-4)(-2)(-3)}=\frac{336}{24}=14$[/tex]

C) [tex]$\frac{(8)(-7)(6)}{(-4)(-2)(-3)}=\frac{-336}{24}=-14$[/tex]

D) [tex]$\frac{(8)(-7)(6)}{(-4)(-2)(-3)}=\frac{-336}{-24}=14$[/tex]


Sagot :

Vamos a resolver el problema paso a paso.

Primero, vamos a calcular el numerador:
[tex]\[ (8)(-7)(6) \][/tex]
Multiplicamos los números:
[tex]\[ 8 \times (-7) = -56 \][/tex]
Luego,
[tex]\[ (-56) \times 6 = -336 \][/tex]
Por lo tanto, el numerador es [tex]\(-336\)[/tex].

Ahora, calculemos el denominador:
[tex]\[ (-4)(-2)(-3) \][/tex]
Multiplicamos los números:
[tex]\[ (-4) \times (-2) = 8 \][/tex]
Luego,
[tex]\[ 8 \times (-3) = -24 \][/tex]
Por lo tanto, el denominador es [tex]\(-24\)[/tex].

Ahora tenemos la fracción:
[tex]\[ \frac{-336}{-24} \][/tex]
Dividimos el numerador por el denominador:
[tex]\[ \frac{-336}{-24} = 14 \][/tex]
El resultado de la operación es [tex]\(14\)[/tex].

Revisemos las opciones dadas para ver cuál coincide con nuestro resultado:

A) [tex]\(\frac{(8)(-7)(6)}{(-4)(-2)(-3)}=\frac{-336}{-24}=-14\)[/tex]

B) [tex]\(\frac{(8)(-7)(6)}{(-4)(-2)(-3)}=\frac{336}{24}=14\)[/tex]

C) [tex]\(\frac{(8)(-7)(6)}{(-4)(-2)(-3)}=\frac{-336}{24}=-14\)[/tex]

D) [tex]\(\frac{(8)(-7)(6)}{(-4)(-2)(-3)}=\frac{-336}{-24}=14\)[/tex]

La opción correcta, que coincide con nuestro resultado, es:
D) [tex]\(\frac{(8)(-7)(6)}{(-4)(-2)(-3)}=\frac{-336}{-24}=14\)[/tex]

Así que, la respuesta correcta es la opción [tex]\(D\)[/tex].
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