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If a heterozygous male with the genotype Ww is mated with a homozygous recessive female of genotype ww, there is a chance that [tex] \quad [/tex] of the offspring will be heterozygous.

\begin{tabular}{|c|c|c|}
\hline
& [tex]$W$[/tex] & [tex]$w$[/tex] \\
\hline
[tex]$w$[/tex] & [tex]$Ww$[/tex] & [tex]$ww$[/tex] \\
\hline
[tex]$w$[/tex] & [tex]$Ww$[/tex] & [tex]$ww$[/tex] \\
\hline
\end{tabular}

If the heterozygous, Ww, is crossed with a homozygous dominant, WW, then the probability of having a homozygous recessive offspring is [tex] \quad [/tex].

\begin{tabular}{|c|c|c|}
\hline
& [tex]$W$[/tex] & [tex]$W$[/tex] \\
\hline
[tex]$w$[/tex] & [tex]$Ww$[/tex] & [tex]$Ww$[/tex] \\
\hline
[tex]$w$[/tex] & [tex]$Ww$[/tex] & [tex]$Ww$[/tex] \\
\hline
\end{tabular}

Sagot :

GinnyAnswer
Let's explore the questions step by step.

1. First Scenario: Crossing a heterozygous male (Ww) with a homozygous recessive female (ww)

The genotypes of the parents are:
- Male (Ww)
- Female (ww)

The possible offspring combinations are:
- W from male and w from female = Ww
- W from male and w from female = Ww
- w from male and w from female = ww
- w from male and w from female = ww

The offspring genotypes are:
- Ww (heterozygous)
- Ww (heterozygous)
- ww (homozygous recessive)
- ww (homozygous recessive)

The breakdown of the possible offspring is:
- 2 heterozygous (Ww)
- 2 homozygous recessive (ww)

Therefore, there is a 2 out of 4, or 0.5, chance that any given offspring will be heterozygous.

2. Second Scenario: Crossing a heterozygous (Ww) with a homozygous dominant (WW)

The genotypes of the parents are:
- Heterozygous (Ww)
- Homozygous dominant (WW)

The possible offspring combinations are:
- W from heterozygous and W from homozygous dominant = WW
- W from heterozygous and W from homozygous dominant = WW
- w from heterozygous and W from homozygous dominant = Ww
- w from heterozygous and W from homozygous dominant = Ww

The offspring genotypes are:
- WW (homozygous dominant)
- WW (homozygous dominant)
- Ww (heterozygous)
- Ww (heterozygous)

Here, there are:
- 2 homozygous dominant (WW)
- 2 heterozygous (Ww)

Therefore, the probability of producing a homozygous recessive (ww) offspring is 0 out of 4, or 0.

Final Answers:

- If a heterozygous male with the genotype Ww is mated with a homozygous recessive female of genotype ww, there is a 0.5 chance that [tex]\(50\%\)[/tex] of the offspring will be heterozygous.
- If the heterozygous, Ww, is crossed with a homozygous dominant, WW, then the probability of having a homozygous recessive offspring is 0.
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