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A business has a budget of [tex]$\$[/tex]720[tex]$ to spend on their marketing campaign. Each month, \(x\), the business spends $[/tex]\[tex]$40$[/tex] on different advertisements. The amount of money remaining in the budget for marketing can be modeled by the function [tex]\(M(x) = -40x + 720\)[/tex].

Based on the graph of the linear function [tex]\(M(x)\)[/tex] and the context of the problem, what is the domain?

A. [tex]\([0,18]\)[/tex]
B. [tex]\([0,720]\)[/tex]
C. [tex]\([0, \infty)\)[/tex]
D. [tex]\(\mathbb{R}\)[/tex]


Sagot :

To determine the domain of the function [tex]\( M(x) = -40x + 720 \)[/tex] given the context of the problem, we need to consider the following factors:

1. Contextual Understanding:
- [tex]\( x \)[/tex] represents the number of months.
- [tex]\( M(x) \)[/tex] represents the remaining budget in dollars.

2. Constraints on [tex]\( x \)[/tex]:
- The number of months [tex]\( x \)[/tex] must be non-negative, so [tex]\( x \geq 0 \)[/tex].
- The business has a finite budget of [tex]$720, which means that after a certain number of months, the budget will be depleted. 3. Finding the Maximum \( x \): - To find when the entire budget is spent, we set \( M(x) = 0 \): \[ 0 = -40x + 720 \] Solving for \( x \): \[ 40x = 720 \] \[ x = \frac{720}{40} = 18 \] 4. Interpreting the Result: - This means after 18 months, the entire $[/tex]720 budget will be spent, and [tex]\( M(x) \)[/tex] will be zero.
- Therefore, [tex]\( x \)[/tex] can range from 0 months (when the campaign starts) to a maximum of 18 months (when the budget is completely used up).

Given these calculations, the domain of the function [tex]\( M(x) \)[/tex] is the set of possible values for [tex]\( x \)[/tex] considering the contextual constraints on the problem.

Thus, the domain is [tex]\([0, 18]\)[/tex], as the number of months [tex]\( x \)[/tex] must be between 0 and 18.