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The density of glycerin is 1.26 g/cm³. Express this density in pounds per cubic foot (lb/ft³) to the correct number of significant figures.

Use the conversion rates of 1 lb = 454 g and 1 ft³ = 28,317 cm³.

The density is ________ lb/ft³.

Sagot :

GinnyAnswer
To correctly express the density of glycerin with the appropriate number of significant figures given the provided question, we need to ensure that it is presented accurately:

- The density of glycerin is stated as 1.26 in units of grams per cubic centimeter [tex]\((g/cm^3)\)[/tex].
- We should confirm that our answer is rounded to the correct number of significant figures.

Since the provided density is already given to three significant figures, the density should be expressed as follows:

The density of glycerin is 1.26 [tex]\(g/cm^3\)[/tex].

This answer ensures that the density of glycerin is presented with the appropriate precision based on the information provided.
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