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What is the equation, in point-slope form, of the line that is perpendicular to the given line and passes through the point [tex][tex]$(-4,-3)$[/tex][/tex]?

A. [tex][tex]$y + 3 = -4(x + 4)$[/tex][/tex]

B. [tex][tex]$y + 3 = -\frac{1}{4}(x + 4)$[/tex][/tex]

C. [tex][tex]$y + 3 = \frac{1}{4}(x + 4)$[/tex][/tex]

D. [tex][tex]$y + 3 = 4(x + 4)$[/tex][/tex]


Sagot :

To find the equation of the line that is perpendicular to the given line and passes through a specific point, we can follow a series of steps. Here is the detailed, step-by-step solution.

1. Identify the slope of the given line:

The given equation of the line is in point-slope form: [tex]\(y + 3 = -4(x + 4)\)[/tex].

In point-slope form, the equation of a line is [tex]\(y - y_1 = m(x - x_1)\)[/tex], where [tex]\(m\)[/tex] is the slope.

From the given equation, we can identify the slope [tex]\(m\)[/tex] as [tex]\(-4\)[/tex].

2. Find the slope of the perpendicular line:

The slope of a line that is perpendicular to another line is the negative reciprocal of the slope of the original line.

Since the slope of the given line is [tex]\(-4\)[/tex], the slope of the perpendicular line will be the negative reciprocal of [tex]\(-4\)[/tex].

The negative reciprocal of [tex]\(-4\)[/tex] is [tex]\(\frac{1}{4}\)[/tex].

3. Use the point-slope form to write the equation of the perpendicular line:

We are given that the perpendicular line passes through the point [tex]\((-4, -3)\)[/tex].

The point-slope form of a line is given by [tex]\(y - y_1 = m(x - x_1)\)[/tex], where:
- [tex]\(m\)[/tex] is the slope of the line
- [tex]\((x_1, y_1)\)[/tex] is a point on the line

Here, [tex]\(m = \(\frac{1}{4}\)[/tex]\) and the point [tex]\((x_1, y_1) = (-4, -3)\)[/tex].

4. Substitute the point and the slope into the point-slope form equation:

[tex]\[ y - (-3) = \frac{1}{4}(x - (-4)) \][/tex]

Simplify the equation:

[tex]\[ y + 3 = \frac{1}{4}(x + 4) \][/tex]

So, the equation, in point-slope form, of the line that is perpendicular to the given line and passes through the point [tex]\((-4, -3)\)[/tex] is:
[tex]\[ y + 3 = \frac{1}{4}(x + 4) \][/tex]

This matches the last option given:
[tex]\[ y + 3 = \frac{1}{4}(x + 4) \][/tex]