Welcome to Westonci.ca, where finding answers to your questions is made simple by our community of experts. Get immediate and reliable answers to your questions from a community of experienced professionals on our platform. Discover in-depth answers to your questions from a wide network of professionals on our user-friendly Q&A platform.

Sets [tex]\( B \)[/tex] and [tex]\( C \)[/tex] are subsets of the universal set [tex]\( U \)[/tex]. These sets are defined as follows:

[tex]\[
\begin{array}{l}
U = \{2, 3, 4, 5, 6, 7\} \\
B = \{3, 4, 5\} \\
C = \{3, 5, 6\}
\end{array}
\][/tex]

Find the following sets. Write your answer in roster form or as [tex]\(\varnothing\)[/tex].

(a) [tex]\((B \cap C)^{\prime} = \square\)[/tex]

(b) [tex]\(B^{\prime} \cup C = \square\)[/tex]

Sagot :

Let's solve the given problem step-by-step.

Given sets are:
[tex]\[ U = \{2, 3, 4, 5, 6, 7\} \][/tex]
[tex]\[ B = \{3, 4, 5\} \][/tex]
[tex]\[ C = \{3, 5, 6\} \][/tex]

### Part (a) [tex]\((B \cap C)^{\prime}\)[/tex]

First, we need to find the intersection of sets [tex]\(B\)[/tex] and [tex]\(C\)[/tex]:
[tex]\[ B \cap C = \{x \mid x \in B \text{ and } x \in C\} \][/tex]

Thus:
[tex]\[ B \cap C = \{3, 5\} \][/tex]

Next, we find the complement of [tex]\(B \cap C\)[/tex] in the universal set [tex]\(U\)[/tex]:
[tex]\[ (B \cap C)^{\prime} = U - (B \cap C) \][/tex]

So:
[tex]\[ (B \cap C)^{\prime} = \{2, 3, 4, 5, 6, 7\} - \{3, 5\} = \{2, 4, 6, 7\} \][/tex]

Therefore:
[tex]\[ (B \cap C)^{\prime} = \{2, 4, 6, 7\} \][/tex]

### Part (b) [tex]\(B^{\prime} \cup C\)[/tex]

First, we need to find the complement of set [tex]\(B\)[/tex] in the universal set [tex]\(U\)[/tex]:
[tex]\[ B^{\prime} = U - B \][/tex]

So:
[tex]\[ B^{\prime} = \{2, 3, 4, 5, 6, 7\} - \{3, 4, 5\} = \{2, 6, 7\} \][/tex]

Next, we find the union of [tex]\(B^{\prime}\)[/tex] and [tex]\(C\)[/tex]:
[tex]\[ B^{\prime} \cup C = \{x \mid x \in B^{\prime} \text{ or } x \in C\} \][/tex]

Thus:
[tex]\[ B^{\prime} = \{2, 6, 7\} \][/tex]
[tex]\[ C = \{3, 5, 6\} \][/tex]

The union is:
[tex]\[ B^{\prime} \cup C = \{2, 6, 7\} \cup \{3, 5, 6\} = \{2, 3, 5, 6, 7\} \][/tex]

Therefore:
[tex]\[ B^{\prime} \cup C = \{2, 3, 5, 6, 7\} \][/tex]

In summary:
(a) [tex]\((B \cap C)^{\prime} = \{2, 4, 6, 7\}\)[/tex]
(b) [tex]\(B^{\prime} \cup C = \{2, 3, 5, 6, 7\}\)[/tex]
Thank you for your visit. We are dedicated to helping you find the information you need, whenever you need it. We appreciate your time. Please come back anytime for the latest information and answers to your questions. Keep exploring Westonci.ca for more insightful answers to your questions. We're here to help.