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Solve for [tex][tex]$x$[/tex][/tex].

[tex]5x - 10 \ \textgreater \ 20 \text{ or } 5x - 10 \leq -15[/tex]

A. [tex]-5 \leq x \ \textless \ 6[/tex]

B. [tex]-1 \leq x \ \textless \ 6[/tex]

C. [tex]x \leq -5 \text{ or } x \ \textgreater \ 6[/tex]

D. [tex]x \leq -1 \text{ or } x \ \textgreater \ 6[/tex]


Sagot :

To solve for [tex]\( x \)[/tex] in the compound inequality:
[tex]\[ 5x - 10 > 20 \text{ or } 5x - 10 \leq -15 \][/tex]
we will break it into two separate inequalities and solve for [tex]\( x \)[/tex] in each part.

### Solving the First Inequality:
[tex]\[ 5x - 10 > 20 \][/tex]

1. Add 10 to both sides:
[tex]\[ 5x - 10 + 10 > 20 + 10 \][/tex]
[tex]\[ 5x > 30 \][/tex]

2. Divide both sides by 5:
[tex]\[ \frac{5x}{5} > \frac{30}{5} \][/tex]
[tex]\[ x > 6 \][/tex]

Thus, the solution to the first inequality is:
[tex]\[ x > 6 \][/tex]

### Solving the Second Inequality:
[tex]\[ 5x - 10 \leq -15 \][/tex]

1. Add 10 to both sides:
[tex]\[ 5x - 10 + 10 \leq -15 + 10 \][/tex]
[tex]\[ 5x \leq -5 \][/tex]

2. Divide both sides by 5:
[tex]\[ \frac{5x}{5} \leq \frac{-5}{5} \][/tex]
[tex]\[ x \leq -1 \][/tex]

Thus, the solution to the second inequality is:
[tex]\[ x \leq -1 \][/tex]

### Combining the Results:
We are looking for the union of the solutions to the two inequalities because we have an "or" condition. Therefore, we combine both solution sets:
[tex]\[ x \leq -1 \text{ or } x > 6 \][/tex]

### Conclusion:
Comparing this result to the provided options, the correct solution is:
[tex]\[ x \leq -1 \text{ or } x > 6 \][/tex]
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