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Sagot :
To solve this problem, we need to fill in the missing values in the frequency table and then find the percentage of students aged 15 and above who travel to school by bus. Here's the step-by-step solution:
### Step 1: Fill in the missing values in the table:
#### Number of students under age 15:
- Traveling by Car: Given as 18.
- Total under 15: Given as 165.
- Total WallyBike: Given as 152.
- Total Bus: Given as 110.
- Total Car: Given as 98.
First, find the number of students under age 15 traveling by bus:
- Subtract the number of students under age 15 who travel by car from the total under 15: [tex]\( 165 - 98 = 67 \)[/tex].
Next, find the number of students under age 15 traveling by WallyBike:
- Subtract the number of students under age 15 traveling by bus (67) from the total WallyBike: [tex]\( 152 - 67 = 85 \)[/tex].
Now we know:
- Students under age 15 traveling by WallyBike: 85.
- Students under age 15 traveling by bus: 67.
#### Number of students aged 15 and above:
- Traveling by Car: We already know the total for car column, and we've subtracted the under 15 group that travels by car, leaving the above group. This ensures the subsequent arithmetic:
Total Bus (city) - Under 15 Bus (67) = 110 - 67 = 43.
Now we know:
- Students aged 15 and above traveling by Bus: 43.
- Given that students aged 15 and above travel by WallyBike: 65.
### Step 2: Calculate the percentage of students aged 15 and above traveling to school by bus:
- Total students aged 15 and above: 195.
- Students aged 15 and above traveling by bus: 43.
Percentage is given by:
[tex]\[ \left( \frac{43}{195} \right) \times 100 \approx 22.05 \% \][/tex]
Rounding this to the nearest whole number:
[tex]\[ 22 \% \][/tex]
So the answer is:
[tex]\(\boxed{22 \%}\)[/tex]
### Completed Frequency Table:
[tex]\[ \begin{tabular}{|l|l|l|l|l|} \hline \multicolumn{5}{|c|}{ Method of Travel to School } \\ \hline & WallyBike & Bus & Car & Row totals \\ \hline Under age 15 & 85 & 67 & 18 & 165 \\ \hline Age 15 and above & 65 & 43 & 80 & 195 \\ \hline Column totals & 152 & 110 & 98 & 360 \\ \hline \end{tabular} \][/tex]
### Step 1: Fill in the missing values in the table:
#### Number of students under age 15:
- Traveling by Car: Given as 18.
- Total under 15: Given as 165.
- Total WallyBike: Given as 152.
- Total Bus: Given as 110.
- Total Car: Given as 98.
First, find the number of students under age 15 traveling by bus:
- Subtract the number of students under age 15 who travel by car from the total under 15: [tex]\( 165 - 98 = 67 \)[/tex].
Next, find the number of students under age 15 traveling by WallyBike:
- Subtract the number of students under age 15 traveling by bus (67) from the total WallyBike: [tex]\( 152 - 67 = 85 \)[/tex].
Now we know:
- Students under age 15 traveling by WallyBike: 85.
- Students under age 15 traveling by bus: 67.
#### Number of students aged 15 and above:
- Traveling by Car: We already know the total for car column, and we've subtracted the under 15 group that travels by car, leaving the above group. This ensures the subsequent arithmetic:
Total Bus (city) - Under 15 Bus (67) = 110 - 67 = 43.
Now we know:
- Students aged 15 and above traveling by Bus: 43.
- Given that students aged 15 and above travel by WallyBike: 65.
### Step 2: Calculate the percentage of students aged 15 and above traveling to school by bus:
- Total students aged 15 and above: 195.
- Students aged 15 and above traveling by bus: 43.
Percentage is given by:
[tex]\[ \left( \frac{43}{195} \right) \times 100 \approx 22.05 \% \][/tex]
Rounding this to the nearest whole number:
[tex]\[ 22 \% \][/tex]
So the answer is:
[tex]\(\boxed{22 \%}\)[/tex]
### Completed Frequency Table:
[tex]\[ \begin{tabular}{|l|l|l|l|l|} \hline \multicolumn{5}{|c|}{ Method of Travel to School } \\ \hline & WallyBike & Bus & Car & Row totals \\ \hline Under age 15 & 85 & 67 & 18 & 165 \\ \hline Age 15 and above & 65 & 43 & 80 & 195 \\ \hline Column totals & 152 & 110 & 98 & 360 \\ \hline \end{tabular} \][/tex]
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