Westonci.ca is your trusted source for finding answers to all your questions. Ask, explore, and learn with our expert community. Get quick and reliable solutions to your questions from a community of seasoned experts on our user-friendly platform. Discover detailed answers to your questions from a wide network of experts on our comprehensive Q&A platform.

The magnitude of an earthquake, [tex]R[/tex], is defined by:

[tex]\[ R = \log_{10}\left(\frac{I_c}{I_n}\right) \][/tex]

where [tex]I_c[/tex] is the intensity of the earthquake (measured by the amplitude of a seismograph reading taken [tex]100 \, \text{km}[/tex] from the epicenter of the earthquake) and [tex]I_n[/tex] is the intensity of a "standard earthquake" (whose amplitude is [tex]1 \, \text{micron} = 10^{-4} \, \text{cm}[/tex]).

The 1906 San Francisco earthquake had a magnitude of [tex]8.3[/tex] on the Richter scale. At the same time in South America, there was an earthquake with a magnitude of [tex]5.3[/tex] that caused only minor damage. How many times more intense was the San Francisco earthquake than the South American one? Round your answer to two decimal places.

The San Francisco earthquake was [tex]\square[/tex] times more intense than the South American earthquake.

Sagot :

To determine how many times more intense the San Francisco earthquake was compared to the South American earthquake, we need to understand the relationship between the magnitudes of the two earthquakes.

The given formula for the magnitude of an earthquake is:
[tex]\[ R = \log_{10}\left(\frac{I_c}{I_n}\right) \][/tex]

Here, [tex]\( I_c \)[/tex] is the intensity of the earthquake and [tex]\( I_n \)[/tex] is the intensity of a standard earthquake.

To find the intensity ratio between the San Francisco earthquake ([tex]\(R_{sf} = 8.3\)[/tex]) and the South American earthquake ([tex]\(R_{sa} = 5.3\)[/tex]), we follow these steps:

1. Express the magnitudes in terms of their intensities:
[tex]\[ R_{sf} = \log_{10}\left(\frac{I_{sf}}{I_n}\right) \][/tex]
[tex]\[ R_{sa} = \log_{10}\left(\frac{I_{sa}}{I_n}\right) \][/tex]

2. Subtract the two equations to find the logarithm of the intensity ratio:
[tex]\[ R_{sf} - R_{sa} = \log_{10}\left(\frac{I_{sf}}{I_n}\right) - \log_{10}\left(\frac{I_{sa}}{I_n}\right) \][/tex]
[tex]\[ 8.3 - 5.3 = \log_{10}\left(\frac{I_{sf}}{I_n}\right) - \log_{10}\left(\frac{I_{sa}}{I_n}\right) \][/tex]
[tex]\[ 3.0 = \log_{10}\left(\frac{I_{sf}}{I_n} \cdot \frac{I_n}{I_{sa}}\right) \][/tex]
[tex]\[ 3.0 = \log_{10}\left(\frac{I_{sf}}{I_{sa}}\right) \][/tex]

3. Use the properties of logarithms to solve for the intensity ratio:
[tex]\[ 10^{3.0} = \frac{I_{sf}}{I_{sa}} \][/tex]

4. Calculate the intensity ratio:
[tex]\[ \frac{I_{sf}}{I_{sa}} = 10^3 = 1000 \][/tex]

Thus, the San Francisco earthquake was 1000 times more intense than the South American earthquake.

Rounded to two decimal places, the San Francisco earthquake was 1000.00 times more intense than the South American earthquake.

Therefore, the San Francisco earthquake was [tex]\(\boxed{1000.00}\)[/tex] times more intense than the South American earthquake.