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To find the experimental probability that exactly 3 of 4 puppies are female, we analyze the provided dataset of coin toss outcomes, where "tails" (T) represents female and "heads" (H) represents male.
The first step is to count all the outcomes that have exactly 3 tails and 1 head.
Given the table:
[tex]\[ \begin{array}{|c|c|c|c|c|} \hline \text{HTHH} & \text{HTTH} & \text{TTTT} & \text{THTT} & \text{HTHT} \\ \hline \text{HHTT} & \text{HHHT} & \text{THHT} & \text{HTTH} & \text{TTHH} \\ \hline \text{HTTT} & \text{HTHT} & \text{TTHH} & \text{THTH} & \text{HTHH} \\ \hline \text{TTHT} & \text{HTTT} & \text{HTHT} & \text{HHHT} & \text{HHHH} \\ \hline \end{array} \][/tex]
We identify all outcomes containing exactly 3 "T"s and 1 "H":
1. THTT
2. HTTT
3. TTHT
4. HTTT (appears again, but we count only distinct events for probability calculation)
Thus, there are [tex]\( 4 \)[/tex] outcomes where exactly 3 out of 4 puppies are female.
Next, we determine the total number of outcomes given in the dataset. As the table shows 5 rows each with 4 outcomes, there are:
[tex]\[ 5 \times 4 = 20 \text{ total outcomes} \][/tex]
To find the experimental probability, we use the formula:
[tex]\[ \text{Probability} = \frac{\text{Number of favorable outcomes}}{\text{Total number of outcomes}} \][/tex]
Substituting the counts:
[tex]\[ \text{Probability} = \frac{4}{20} = 0.2 \][/tex]
Therefore, the experimental probability that exactly 3 of 4 puppies are female is:
[tex]\[ \boxed{0.2} \][/tex]
The first step is to count all the outcomes that have exactly 3 tails and 1 head.
Given the table:
[tex]\[ \begin{array}{|c|c|c|c|c|} \hline \text{HTHH} & \text{HTTH} & \text{TTTT} & \text{THTT} & \text{HTHT} \\ \hline \text{HHTT} & \text{HHHT} & \text{THHT} & \text{HTTH} & \text{TTHH} \\ \hline \text{HTTT} & \text{HTHT} & \text{TTHH} & \text{THTH} & \text{HTHH} \\ \hline \text{TTHT} & \text{HTTT} & \text{HTHT} & \text{HHHT} & \text{HHHH} \\ \hline \end{array} \][/tex]
We identify all outcomes containing exactly 3 "T"s and 1 "H":
1. THTT
2. HTTT
3. TTHT
4. HTTT (appears again, but we count only distinct events for probability calculation)
Thus, there are [tex]\( 4 \)[/tex] outcomes where exactly 3 out of 4 puppies are female.
Next, we determine the total number of outcomes given in the dataset. As the table shows 5 rows each with 4 outcomes, there are:
[tex]\[ 5 \times 4 = 20 \text{ total outcomes} \][/tex]
To find the experimental probability, we use the formula:
[tex]\[ \text{Probability} = \frac{\text{Number of favorable outcomes}}{\text{Total number of outcomes}} \][/tex]
Substituting the counts:
[tex]\[ \text{Probability} = \frac{4}{20} = 0.2 \][/tex]
Therefore, the experimental probability that exactly 3 of 4 puppies are female is:
[tex]\[ \boxed{0.2} \][/tex]
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