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\begin{tabular}{|c|c|c|c|c|c|}
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& 115303 & 3229 & 191 & 18 & \\
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& [tex]$2 \div 5 \longdiv { 3 2 3 }$[/tex] & & & & \\
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(Note: The last two lines contain garbled text that seems to be nonsensical. Without more context, it's challenging to correct. If you meant to include a meaningful sentence or instruction, please provide the correct wording.)

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Sagot :

GinnyAnswer
To solve the equation [tex]\(4(18 - 3k) = 9(k + 1)\)[/tex], we need to follow these steps:

1. Distribute the 4 on the left side:
[tex]\[ 4(18 - 3k) = 4 \cdot 18 - 4 \cdot 3k = 72 - 12k \][/tex]

2. Distribute the 9 on the right side:
[tex]\[ 9(k + 1) = 9 \cdot k + 9 \cdot 1 = 9k + 9 \][/tex]

3. Set the two expressions equal to each other:
[tex]\[ 72 - 12k = 9k + 9 \][/tex]

4. Combine like terms by moving all the [tex]\(k\)[/tex]-terms to one side and constants to the other:
[tex]\[ 72 - 12k = 9k + 9 \][/tex]
Subtract [tex]\(9k\)[/tex] from both sides:
[tex]\[ 72 - 12k - 9k = 9 \][/tex]
This simplifies to:
[tex]\[ 72 - 21k = 9 \][/tex]

5. Isolate the [tex]\(k\)[/tex]-term by subtracting 72 from both sides:
[tex]\[ -21k = 9 - 72 \][/tex]
Simplify the constant on the right side:
[tex]\[ -21k = -63 \][/tex]

6. Solve for [tex]\(k\)[/tex] by dividing both sides by [tex]\(-21\)[/tex]:
[tex]\[ k = \frac{-63}{-21} \][/tex]
Simplify the fraction:
[tex]\[ k = 3 \][/tex]

Thus, the solution to the equation [tex]\(4(18 - 3k) = 9(k + 1)\)[/tex] is:
[tex]\[ k = 3 \][/tex]
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