Discover answers to your questions with Westonci.ca, the leading Q&A platform that connects you with knowledgeable experts. Get detailed and accurate answers to your questions from a community of experts on our comprehensive Q&A platform. Join our Q&A platform to connect with experts dedicated to providing accurate answers to your questions in various fields.
Sagot :
To determine the coordinates of point [tex]\( M \)[/tex], we need to go through a step-by-step process of finding the intermediate point [tex]\( L \)[/tex] and then [tex]\( M \)[/tex].
### Step 1: Finding Point [tex]\( L \)[/tex]
Point [tex]\( L \)[/tex] partitions the directed line segment [tex]\( K(-6,-2) \)[/tex] to [tex]\( N(8,3) \)[/tex] in the ratio [tex]\( 1:2 \)[/tex].
- The formula for finding the coordinates [tex]\((x, y)\)[/tex] of a point that divides a segment in the ratio [tex]\( m:n \)[/tex] is:
[tex]\[ x = \frac{m \cdot x_2 + n \cdot x_1}{m + n} \][/tex]
[tex]\[ y = \frac{m \cdot y_2 + n \cdot y_1}{m + n} \][/tex]
- Plugging the values for point [tex]\( L \)[/tex]:
- [tex]\( K = (x_1, y_1) = (-6, -2) \)[/tex]
- [tex]\( N = (x_2, y_2) = (8, 3) \)[/tex]
- [tex]\( m = 1 \)[/tex], [tex]\( n = 2 \)[/tex]
[tex]\[ l_x = \frac{1 \times 8 + 2 \times (-6)}{1+2} = \frac{8 - 12}{3} = \frac{-4}{3} = -1.3333 \][/tex]
[tex]\[ l_y = \frac{1 \times 3 + 2 \times (-2)}{1+2} = \frac{3 - 4}{3} = \frac{-1}{3} = -0.3333 \][/tex]
So, the coordinates of point [tex]\( L \)[/tex] are approximately [tex]\((-1.3333, -0.3333)\)[/tex].
### Step 2: Finding Point [tex]\( M \)[/tex]
Point [tex]\( M \)[/tex] partitions the directed line segment from [tex]\( L(-1.3333, -0.3333) \)[/tex] to [tex]\( N(8, 3) \)[/tex] in the ratio [tex]\( 3:1 \)[/tex].
- Using the same formula as before:
[tex]\[ m_x = \frac{3 \cdot 8 + 1 \cdot (-1.3333)}{3+1} = \frac{24 - 1.3333}{4} = \frac{22.6667}{4} = 5.6667 \][/tex]
[tex]\[ m_y = \frac{3 \cdot 3 + 1 \cdot (-0.3333)}{3+1} = \frac{9 - 0.3333}{4} = \frac{8.6667}{4} = 2.1667 \][/tex]
### Step 3: Rounding to the Nearest Tenth
Finally, we round the coordinates of point [tex]\( M \)[/tex] to the nearest tenth:
- [tex]\( m_x \approx 5.7 \)[/tex]
- [tex]\( m_y \approx 2.2 \)[/tex]
Thus, the coordinates of point [tex]\( M \)[/tex] are [tex]\( (5.7, 2.2) \)[/tex].
So, the correct answer is:
[tex]\[ (5.7, 2.2) \][/tex]
### Step 1: Finding Point [tex]\( L \)[/tex]
Point [tex]\( L \)[/tex] partitions the directed line segment [tex]\( K(-6,-2) \)[/tex] to [tex]\( N(8,3) \)[/tex] in the ratio [tex]\( 1:2 \)[/tex].
- The formula for finding the coordinates [tex]\((x, y)\)[/tex] of a point that divides a segment in the ratio [tex]\( m:n \)[/tex] is:
[tex]\[ x = \frac{m \cdot x_2 + n \cdot x_1}{m + n} \][/tex]
[tex]\[ y = \frac{m \cdot y_2 + n \cdot y_1}{m + n} \][/tex]
- Plugging the values for point [tex]\( L \)[/tex]:
- [tex]\( K = (x_1, y_1) = (-6, -2) \)[/tex]
- [tex]\( N = (x_2, y_2) = (8, 3) \)[/tex]
- [tex]\( m = 1 \)[/tex], [tex]\( n = 2 \)[/tex]
[tex]\[ l_x = \frac{1 \times 8 + 2 \times (-6)}{1+2} = \frac{8 - 12}{3} = \frac{-4}{3} = -1.3333 \][/tex]
[tex]\[ l_y = \frac{1 \times 3 + 2 \times (-2)}{1+2} = \frac{3 - 4}{3} = \frac{-1}{3} = -0.3333 \][/tex]
So, the coordinates of point [tex]\( L \)[/tex] are approximately [tex]\((-1.3333, -0.3333)\)[/tex].
### Step 2: Finding Point [tex]\( M \)[/tex]
Point [tex]\( M \)[/tex] partitions the directed line segment from [tex]\( L(-1.3333, -0.3333) \)[/tex] to [tex]\( N(8, 3) \)[/tex] in the ratio [tex]\( 3:1 \)[/tex].
- Using the same formula as before:
[tex]\[ m_x = \frac{3 \cdot 8 + 1 \cdot (-1.3333)}{3+1} = \frac{24 - 1.3333}{4} = \frac{22.6667}{4} = 5.6667 \][/tex]
[tex]\[ m_y = \frac{3 \cdot 3 + 1 \cdot (-0.3333)}{3+1} = \frac{9 - 0.3333}{4} = \frac{8.6667}{4} = 2.1667 \][/tex]
### Step 3: Rounding to the Nearest Tenth
Finally, we round the coordinates of point [tex]\( M \)[/tex] to the nearest tenth:
- [tex]\( m_x \approx 5.7 \)[/tex]
- [tex]\( m_y \approx 2.2 \)[/tex]
Thus, the coordinates of point [tex]\( M \)[/tex] are [tex]\( (5.7, 2.2) \)[/tex].
So, the correct answer is:
[tex]\[ (5.7, 2.2) \][/tex]
We appreciate your visit. Our platform is always here to offer accurate and reliable answers. Return anytime. Your visit means a lot to us. Don't hesitate to return for more reliable answers to any questions you may have. Stay curious and keep coming back to Westonci.ca for answers to all your burning questions.