Welcome to Westonci.ca, where curiosity meets expertise. Ask any question and receive fast, accurate answers from our knowledgeable community. Connect with a community of experts ready to help you find solutions to your questions quickly and accurately. Connect with a community of professionals ready to provide precise solutions to your questions quickly and accurately.

APUNTES DE FÍSICA II: CINEMÁTICA Y DINÁMICA

3. Determina el trabajo realizado al desplazar un bloque 3 m sobre una superficie horizontal, si se desprecia la fricción y la fuerza aplicada tiene una magnitud de 25 N.


Sagot :

Final answer:

The work done when moving a block 3 m with a force of 25 N on a horizontal surface is 75 Joules.


Explanation:

Work done is calculated by multiplying the force applied by the displacement and the cos of the angle between the force and displacement. In this case, work = force x displacement x cos(angle).

Given force of 25 N, displacement of 3 m, and angle of 0°, work = 25 N x 3 m x cos(0°) = 75 Joules.

Therefore, the work done when moving a block 3 m with a force of 25 N on a horizontal surface is 75 Joules.


Learn more about work calculation in physics here:

https://brainly.com/question/33726554


We appreciate your time. Please revisit us for more reliable answers to any questions you may have. Thanks for using our service. We're always here to provide accurate and up-to-date answers to all your queries. Stay curious and keep coming back to Westonci.ca for answers to all your burning questions.