To determine the work done when carrying a book weighing 2.0 newtons at a constant velocity over a horizontal distance of 26 meters, we need to consider the definition of work in physics.
Work is calculated using the formula:
[tex]\[ \text{Work} = \text{Force} \times \text{Distance} \times \cos(\theta) \][/tex]
Here, [tex]\(\theta\)[/tex] is the angle between the force applied and the direction of motion.
When carrying a book horizontally at constant velocity:
1. The weight of the book acts vertically downward due to gravity.
2. The movement is horizontal.
3. The angle [tex]\(\theta\)[/tex] between the direction of the weight (force due to gravity) and the direction of the motion (horizontal) is 90 degrees.
The cosine of 90 degrees ([tex]\(\cos(90^\circ)\)[/tex]) is 0.
Substituting into the formula, we get:
[tex]\[ \text{Work} = \text{Force} \times \text{Distance} \times \cos(90^\circ) \][/tex]
[tex]\[ \text{Work} = 2.0 \, \text{N} \times 26 \, \text{m} \times 0 \][/tex]
[tex]\[ \text{Work} = 0 \, \text{J} \][/tex]
Therefore, the work done is:
[tex]\[ 0.0 \, \text{J} \][/tex]
Among the given options, the correct answer is:
[tex]\[ \boxed{0.0 \, \text{J}} \][/tex]
