Get the answers you need at Westonci.ca, where our expert community is always ready to help with accurate information. Get quick and reliable solutions to your questions from a community of experienced experts on our platform. Discover in-depth answers to your questions from a wide network of professionals on our user-friendly Q&A platform.
Sagot :
Let's solve the problem step-by-step.
We need to identify the correct equation that relates kinetic energy ([tex]\( KE \)[/tex]), mass ([tex]\( m \)[/tex]), and velocity ([tex]\( v \)[/tex]).
The formula for kinetic energy is derived from the principles of physics, specifically from the work-energy theorem. For an object with mass [tex]\( m \)[/tex] moving with velocity [tex]\( v \)[/tex], the kinetic energy is mathematically given by:
[tex]\[ KE = \frac{1}{2} m v^2 \][/tex]
Let's analyze the given options:
A. [tex]\( KE = \frac{1}{2} m^2 v \)[/tex]
Here, the mass [tex]\( m \)[/tex] is squared and the velocity [tex]\( v \)[/tex] is to the first power. This form is incorrect because kinetic energy does not involve mass squared, and velocity should be squared.
B. [tex]\( KE = \frac{1}{2} m v^2 \)[/tex]
This matches our earlier stated formula for kinetic energy. The mass [tex]\( m \)[/tex] and the square of velocity [tex]\( v \)[/tex] are correctly included. Therefore, this looks like the correct option.
C. [tex]\( KE = \frac{1}{2} m v \)[/tex]
In this option, both mass [tex]\( m \)[/tex] and velocity [tex]\( v \)[/tex] are to the first power. This does not correctly represent kinetic energy because velocity should be squared, not to the first power.
D. [tex]\( KE = \frac{1}{2} m v^3 \)[/tex]
Here, the velocity [tex]\( v \)[/tex] is cubed. This is incorrect because kinetic energy involves the square of velocity, not the cube.
After reviewing all choices, the correct relationship is:
[tex]\[ \boxed{KE = \frac{1}{2} m v^2} \][/tex]
Therefore, the correct answer is:
B. [tex]\( KE = \frac{1}{2} m v^2 \)[/tex]
We need to identify the correct equation that relates kinetic energy ([tex]\( KE \)[/tex]), mass ([tex]\( m \)[/tex]), and velocity ([tex]\( v \)[/tex]).
The formula for kinetic energy is derived from the principles of physics, specifically from the work-energy theorem. For an object with mass [tex]\( m \)[/tex] moving with velocity [tex]\( v \)[/tex], the kinetic energy is mathematically given by:
[tex]\[ KE = \frac{1}{2} m v^2 \][/tex]
Let's analyze the given options:
A. [tex]\( KE = \frac{1}{2} m^2 v \)[/tex]
Here, the mass [tex]\( m \)[/tex] is squared and the velocity [tex]\( v \)[/tex] is to the first power. This form is incorrect because kinetic energy does not involve mass squared, and velocity should be squared.
B. [tex]\( KE = \frac{1}{2} m v^2 \)[/tex]
This matches our earlier stated formula for kinetic energy. The mass [tex]\( m \)[/tex] and the square of velocity [tex]\( v \)[/tex] are correctly included. Therefore, this looks like the correct option.
C. [tex]\( KE = \frac{1}{2} m v \)[/tex]
In this option, both mass [tex]\( m \)[/tex] and velocity [tex]\( v \)[/tex] are to the first power. This does not correctly represent kinetic energy because velocity should be squared, not to the first power.
D. [tex]\( KE = \frac{1}{2} m v^3 \)[/tex]
Here, the velocity [tex]\( v \)[/tex] is cubed. This is incorrect because kinetic energy involves the square of velocity, not the cube.
After reviewing all choices, the correct relationship is:
[tex]\[ \boxed{KE = \frac{1}{2} m v^2} \][/tex]
Therefore, the correct answer is:
B. [tex]\( KE = \frac{1}{2} m v^2 \)[/tex]
We hope our answers were helpful. Return anytime for more information and answers to any other questions you may have. We hope you found this helpful. Feel free to come back anytime for more accurate answers and updated information. Get the answers you need at Westonci.ca. Stay informed by returning for our latest expert advice.