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Consider the following intermediate chemical equations.

[tex]\[
\begin{array}{l}
CH_4(g) + 2O_2(g) \rightarrow CO_2(g) + 2H_2O(g) \\
2H_2O(g) \rightarrow 2H_2O(l)
\end{array}
\][/tex]

Which overall chemical equation is obtained by combining these intermediate equations?

A. [tex]\(CH_4(g) + 2O_2(g) \rightarrow CO_2(g) + 2H_2O(l)\)[/tex]

B. [tex]\(CH_4(g) + 2O_2(g) \rightarrow CO_2(g) + 2H_2O(g)\)[/tex]

C. [tex]\(CH_4(g) + 2O_2(g) \rightarrow CO_2(g) + 4H_2O(g) + 2H_2O(l)\)[/tex]

D. [tex]\(CH_4(g) + 2O_2(g) \rightarrow CO_2(g) + 6H_2O(g)\)[/tex]

Sagot :

GinnyAnswer
To find the overall chemical equation obtained by combining the two intermediate equations, let's analyze each step and combine them systematically.

The given intermediate reactions are:
1. [tex]\( CH_4(g) + 2O_2(g) \rightarrow CO_2(g) + 2H_2O(g) \)[/tex]
2. [tex]\( 2H_2O(g) \rightarrow 2H_2O(l) \)[/tex]

To combine these equations, we add them together, ensuring that identical species on opposite sides of the equations cancel each other out where applicable. Here’s the step-by-step process:

1. Write down the first chemical equation:
[tex]\[ CH_4(g) + 2O_2(g) \rightarrow CO_2(g) + 2H_2O(g) \][/tex]
2. Write down the second chemical equation:
[tex]\[ 2H_2O(g) \rightarrow 2H_2O(l) \][/tex]
3. Add the equations together.

When combining, note that the [tex]\( 2H_2O(g) \)[/tex] produced in the first reaction will be consumed in the second reaction:

[tex]\[ CH_4(g) + 2O_2(g) \rightarrow CO_2(g) + 2H_2O(g) \][/tex]
[tex]\[ 2H_2O(g) \rightarrow 2H_2O(l) \][/tex]

The [tex]\( 2H_2O(g) \)[/tex]’s will cancel each other out:

[tex]\[ CH_4(g) + 2O_2(g) \rightarrow CO_2(g) + 2H_2O(l) \][/tex]

Therefore, the overall chemical equation that represents the complete process is:

[tex]\[ CH_4(g) + 2O_2(g) \rightarrow CO_2(g) + 2H_2O(l) \][/tex]

So, the correct answer is:

[tex]\[ CH_4(g) + 2O_2(g) \rightarrow CO_2(g) + 2H_2O(l) \][/tex]
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