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Sagot :
To determine the rate change and calculate the new rate based on the given protocol and the patient's aPTT value, follow these steps:
1. Identify the current infusion rate:
- The initial infusion rate is given as [tex]\(28 \, \text{mL/h}\)[/tex].
2. Determine the patient’s aPTT value:
- The patient's aPTT value given in the problem is [tex]\(110\)[/tex].
3. Refer to the aPTT protocol table:
- According to the protocol:
- If the aPTT is [tex]\(91-110\)[/tex] seconds, the rate should decrease by [tex]\(1 \, \text{unit/kgh}\)[/tex].
4. Calculate the rate change:
- The rate change corresponding to an aPTT of [tex]\(110\)[/tex] is a decrease by [tex]\(1 \, \text{unit/kgh}\)[/tex].
5. Apply the rate change to the initial infusion rate:
- Initial rate: [tex]\(28 \, \text{mL/h}\)[/tex]
- Decrease by: [tex]\(1 \, \text{mL/h}\)[/tex]
6. Calculate the new rate:
- New rate = Initial rate - Rate change
- New rate = [tex]\(28 \, \text{mL/h} - 1 \, \text{mL/h} = 27 \, \text{mL/h}\)[/tex]
Thus, the new infusion rate will be [tex]\(27 \, \text{mL/h}\)[/tex].
Answer: [tex]\(\mathbf{27 \, \text{mL/h}}\)[/tex]
1. Identify the current infusion rate:
- The initial infusion rate is given as [tex]\(28 \, \text{mL/h}\)[/tex].
2. Determine the patient’s aPTT value:
- The patient's aPTT value given in the problem is [tex]\(110\)[/tex].
3. Refer to the aPTT protocol table:
- According to the protocol:
- If the aPTT is [tex]\(91-110\)[/tex] seconds, the rate should decrease by [tex]\(1 \, \text{unit/kgh}\)[/tex].
4. Calculate the rate change:
- The rate change corresponding to an aPTT of [tex]\(110\)[/tex] is a decrease by [tex]\(1 \, \text{unit/kgh}\)[/tex].
5. Apply the rate change to the initial infusion rate:
- Initial rate: [tex]\(28 \, \text{mL/h}\)[/tex]
- Decrease by: [tex]\(1 \, \text{mL/h}\)[/tex]
6. Calculate the new rate:
- New rate = Initial rate - Rate change
- New rate = [tex]\(28 \, \text{mL/h} - 1 \, \text{mL/h} = 27 \, \text{mL/h}\)[/tex]
Thus, the new infusion rate will be [tex]\(27 \, \text{mL/h}\)[/tex].
Answer: [tex]\(\mathbf{27 \, \text{mL/h}}\)[/tex]
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