Discover a wealth of knowledge at Westonci.ca, where experts provide answers to your most pressing questions. Get precise and detailed answers to your questions from a knowledgeable community of experts on our Q&A platform. Get precise and detailed answers to your questions from a knowledgeable community of experts on our Q&A platform.
Sagot :
To solve the problem, we need to follow the given steps and find the time period speed of the electron with provided data:
### Step 1: Understand the given data
- Current (I): 1.1 milliamps (mA)
- Charge on an electron (e): [tex]\(1.6 \times 10^{-19}\)[/tex] Coulombs (C)
### Step 2: Convert current from milliamps to amps
Current in milliamps (mA) must be converted to amps (A), where 1 A = 1000 mA.
[tex]\[1.1 \text{ mA} = 1.1 \times 10^{-3} \text{ A}\][/tex]
### Step 3: Calculate the number of electrons passing per second
Current ([tex]\(I\)[/tex]) is defined as the rate of flow of charge ([tex]\(Q\)[/tex]) per unit time ([tex]\(t\)[/tex]):
[tex]\[ I = \frac{Q}{t} \][/tex]
Rearranging this formula to solve for the charge ([tex]\(Q\)[/tex]) over time:
[tex]\[ Q = I \times t \][/tex]
But, since we are focusing on the number of electrons per second, we next find out how many elementary charges ([tex]\(e\)[/tex]) pass in one second.
[tex]\[ \text{Number of electrons per second} = \frac{I}{e} \][/tex]
Given the current ([tex]\(I\)[/tex]) in amps (A) and the charge of an electron ([tex]\(e\)[/tex]) in Coulombs (C):
[tex]\[ \text{Number of electrons per second} = \frac{1.1 \times 10^{-3} \text{ A}}{1.6 \times 10^{-19} \text{ C}} \][/tex]
### Step 4: Calculate the numerical result
From the known values provided:
- Current ([tex]\(I\)[/tex]) = 0.0011 A
- Charge of an electron ([tex]\(e\)[/tex]) = [tex]\(1.6 \times 10^{-19}\)[/tex] C
[tex]\[ \text{Number of electrons per second} = 0.0011 A \times \left(\frac{1}{1.6 \times 10^{-19} \text{ C}}\right) \][/tex]
[tex]\[ \text{Number of electrons per second} = 6.875 \times 10^{15} \text{ electrons/second} \][/tex]
### Final Results
- Current in Amps: 0.0011 A
- Number of electrons passing per second: [tex]\(6.875 \times 10^{15}\)[/tex] electrons/second
This indicates that for a current of 1.1 mA, approximately [tex]\(6.875 \times 10^{15}\)[/tex] electrons pass through the conductor per second.
### Step 1: Understand the given data
- Current (I): 1.1 milliamps (mA)
- Charge on an electron (e): [tex]\(1.6 \times 10^{-19}\)[/tex] Coulombs (C)
### Step 2: Convert current from milliamps to amps
Current in milliamps (mA) must be converted to amps (A), where 1 A = 1000 mA.
[tex]\[1.1 \text{ mA} = 1.1 \times 10^{-3} \text{ A}\][/tex]
### Step 3: Calculate the number of electrons passing per second
Current ([tex]\(I\)[/tex]) is defined as the rate of flow of charge ([tex]\(Q\)[/tex]) per unit time ([tex]\(t\)[/tex]):
[tex]\[ I = \frac{Q}{t} \][/tex]
Rearranging this formula to solve for the charge ([tex]\(Q\)[/tex]) over time:
[tex]\[ Q = I \times t \][/tex]
But, since we are focusing on the number of electrons per second, we next find out how many elementary charges ([tex]\(e\)[/tex]) pass in one second.
[tex]\[ \text{Number of electrons per second} = \frac{I}{e} \][/tex]
Given the current ([tex]\(I\)[/tex]) in amps (A) and the charge of an electron ([tex]\(e\)[/tex]) in Coulombs (C):
[tex]\[ \text{Number of electrons per second} = \frac{1.1 \times 10^{-3} \text{ A}}{1.6 \times 10^{-19} \text{ C}} \][/tex]
### Step 4: Calculate the numerical result
From the known values provided:
- Current ([tex]\(I\)[/tex]) = 0.0011 A
- Charge of an electron ([tex]\(e\)[/tex]) = [tex]\(1.6 \times 10^{-19}\)[/tex] C
[tex]\[ \text{Number of electrons per second} = 0.0011 A \times \left(\frac{1}{1.6 \times 10^{-19} \text{ C}}\right) \][/tex]
[tex]\[ \text{Number of electrons per second} = 6.875 \times 10^{15} \text{ electrons/second} \][/tex]
### Final Results
- Current in Amps: 0.0011 A
- Number of electrons passing per second: [tex]\(6.875 \times 10^{15}\)[/tex] electrons/second
This indicates that for a current of 1.1 mA, approximately [tex]\(6.875 \times 10^{15}\)[/tex] electrons pass through the conductor per second.
We hope this information was helpful. Feel free to return anytime for more answers to your questions and concerns. We appreciate your time. Please come back anytime for the latest information and answers to your questions. Westonci.ca is your trusted source for answers. Visit us again to find more information on diverse topics.