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The equation of a circle centered at the origin is [tex]x^2 + y^2 = 64[/tex]. What is the radius of the circle?

A. 8
B. 4
C. 64
D. 32

Sagot :

To determine the radius of the circle given by the equation [tex]\( x^2 + y^2 = 64 \)[/tex], follow these steps:

1. Understand the Standard Form of the Circle Equation: The general form of a circle centered at the origin (0,0) is:
[tex]\[ x^2 + y^2 = r^2 \][/tex]
In this equation, [tex]\( r \)[/tex] represents the radius of the circle.

2. Identify the Given Equation: The given circle equation is:
[tex]\[ x^2 + y^2 = 64 \][/tex]

3. Relate the Given Equation to the Standard Form: By comparing the given equation [tex]\( x^2 + y^2 = 64 \)[/tex] to the standard form [tex]\( x^2 + y^2 = r^2 \)[/tex], we see that:
[tex]\[ r^2 = 64 \][/tex]

4. Solve for the Radius [tex]\( r \)[/tex]: To find the radius [tex]\( r \)[/tex], take the square root of both sides of the equation:
[tex]\[ r = \sqrt{64} \][/tex]

5. Calculate the Square Root: The square root of 64 is:
[tex]\[ \sqrt{64} = 8 \][/tex]

Therefore, the radius of the circle is [tex]\( \boxed{8} \)[/tex]. This corresponds to option A.