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Sagot :
13 L is left in the tank after 11 days
Work
To solve this problem, we can use the exponential decay formula which is:
V = P(r)^t
Where:
V = value
p = initial amount
r = rate
t = time
In this case, our values would be:
V = ?
p = 26624
r = 0.50
t = 11
Substitute the values in and solve.
V = 26624(0.50)^11
V = 13
Thus, 13 litres will remain in the tank on the 11th day.
Answer:
[tex]13\; {\rm L}[/tex].
Step-by-step explanation:
Start by listing the amount of water in the tank after each day, relative to the original volume of water in the tank:
- After [tex]1[/tex] day: [tex](1/2) \times 1 = (1/2)[/tex] of the original volume.
- After [tex]2[/tex] days: [tex](1/2) \times (1/2) = (1/2^{2}) = (1/4)[/tex] of the original volume.
- After [tex]3[/tex] days: [tex](1/2) \times ((1/2) \times (1/2)) = (1/2^{3}) = (1/8)[/tex] of the original volume.
Observe that after [tex]n[/tex] days, the volume in the tank would be [tex](1/2^{n})[/tex] the original volume. Hence, after [tex]n = 11[/tex] days, the volume in the tank would be [tex](1/2^{11}) = (1/2048)[/tex] of the original volume:
[tex]\displaystyle \frac{1}{2048} \times 26\, 624\; {\rm L} = 13\; {\rm L}[/tex].
In other words, there would be [tex]13\; {\rm L}[/tex] of water in the tank after [tex]11[/tex] days.
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