13 L is left in the tank after 11 days
To solve this problem, we can use the exponential decay formula which is:
V = P(r)^t
Where:
V = value
p = initial amount
r = rate
t = time
In this case, our values would be:
V = ?
p = 26624
r = 0.50
t = 11
Substitute the values in and solve.
V = 26624(0.50)^11
V = 13
Thus, 13 litres will remain in the tank on the 11th day.
Answer:
[tex]13\; {\rm L}[/tex].
Step-by-step explanation:
Start by listing the amount of water in the tank after each day, relative to the original volume of water in the tank:
Observe that after [tex]n[/tex] days, the volume in the tank would be [tex](1/2^{n})[/tex] the original volume. Hence, after [tex]n = 11[/tex] days, the volume in the tank would be [tex](1/2^{11}) = (1/2048)[/tex] of the original volume:
[tex]\displaystyle \frac{1}{2048} \times 26\, 624\; {\rm L} = 13\; {\rm L}[/tex].
In other words, there would be [tex]13\; {\rm L}[/tex] of water in the tank after [tex]11[/tex] days.
