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Given the chemical equation:
[tex]\[ 3 H_2SO_4 + 2 B(OH)_3 \rightarrow B_2(SO_4)_3 + 6 H_2O \][/tex]

What is the mole ratio between sulfuric acid and boron hydroxide?
[tex]\[ \frac{3 \text{ mol } H_2SO_4}{2 \text{ mol } B(OH)_3} \][/tex]

Sagot :

GinnyAnswer
Let's analyze the balanced chemical equation:

[tex]\[ 3 H_2SO_4 + 2 B(OH)_3 \rightarrow B_2(SO_4)_3 + 6 H_2O \][/tex]

From the equation, we observe that the stoichiometric coefficients for sulfuric acid (H[tex]\(_2\)[/tex]SO[tex]\(_4\)[/tex]) and boron hydroxide (B(OH)[tex]\(_3\)[/tex]) are 3 and 2, respectively. These coefficients indicate the mole ratio in which these substances react.

To determine the mole ratio between sulfuric acid and boron hydroxide, we directly use the coefficients from the balanced chemical equation:

[tex]\[ \frac{3 \text{ mol H}_2\text{SO}_4}{2 \text{ mol B(OH)}_3} \][/tex]

Therefore, the mole ratio between sulfuric acid (H[tex]\(_2\)[/tex]SO[tex]\(_4\)[/tex]) and boron hydroxide (B(OH)[tex]\(_3\)[/tex]) is [tex]\( \frac{3 \text{ mol H}_2\text{SO}_4}{2 \text{ mol B(OH)}_3} \)[/tex].
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