To determine the ratio between ethanol and the energy of the reaction, we need to take a closer look at the balanced chemical equation provided:
[tex]\[ \text{C}_2\text{H}_5\text{OH} + 2 \text{O}_2 \rightarrow 2 \text{CO}_2 + 3 \text{H}_2\text{O} + 1367 \text{ kJ} \][/tex]
From this equation, we can see that:
1. One mole of ethanol (C₂H₅OH) reacts with two moles of oxygen (O₂) to produce two moles of carbon dioxide (CO₂), three moles of water (H₂O), and releases 1367 kJ of energy.
Therefore, the ratio between the moles of ethanol and the energy released in the reaction can be summarized as:
- 1 mole of C₂H₅OH corresponds to 1367 kJ of energy.
So, the ratio can be written as:
[tex]\[ 1 \text{ mole C}_2\text{H}_5\text{OH} : 1367 \text{ kJ} \][/tex]
Thus, the ratio is:
[tex]\[ \boxed{1} \text{ mole C}_2\text{H}_5\text{OH} \][/tex]
[tex]\[ \boxed{1367} \text{ kJ} \][/tex]
