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How many moles of [tex]FeO[/tex] are produced if 8 moles of [tex]SO_2[/tex] are produced?

[tex]\[2 CuFeS_2 + 5 O_2 \rightarrow 2 Cu + 2 FeO + 4 SO_2\][/tex]

[?] mol [tex]FeO[/tex]

Sagot :

GinnyAnswer
To determine how many moles of FeO are produced if 8 moles of [tex]\( SO_2 \)[/tex] are produced, we need to use the stoichiometric relationship provided by the balanced chemical equation:
[tex]\[ 2 \, \text{CuFeS}_2 + 5 \, \text{O}_2 \rightarrow 2 \, \text{Cu} + 2 \, \text{FeO} + 4 \, \text{SO}_2 \][/tex]

1. From the balanced equation, we observe that for every 2 moles of FeO produced, 4 moles of [tex]\( SO_2 \)[/tex] are produced. This simplifies to a 1:2 stoichiometric ratio between FeO and [tex]\( SO_2 \)[/tex].

2. We are given that 8 moles of [tex]\( SO_2 \)[/tex] are produced. Based on the stoichiometric ratio (1 mole of FeO for every 2 moles of [tex]\( SO_2 \)[/tex]):

[tex]\[ \text{Moles of FeO} = 8 \, \text{moles of SO}_2 \times \left( \frac{1 \, \text{mole of FeO}}{2 \, \text{moles of SO}_2} \right) \][/tex]

3. Simplifying this calculation:

[tex]\[ \text{Moles of FeO} = 8 \times 0.5 = 4.0 \][/tex]

Therefore, if 8 moles of [tex]\( SO_2 \)[/tex] are produced, 4.0 moles of FeO are also produced.
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