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The equation to perform the calculation is shown below.
[tex]\[ 3.45 \, \text{mol} \, \text{KMnO}_4 \times \frac{8 \, \text{mol} \, \text{H}_2\text{O}}{2 \, \text{mol} \, \text{KMnO}_4} \][/tex]

Did you set up the equation correctly?

A. Yes, and I got the correct answer.
B. Yes, but I got the wrong answer because I made a mathematical error.
C. No, I did not set up the equation correctly.


Sagot :

To solve this problem, let’s break it down step-by-step:

1. Understanding the problem:
- We start with 3.45 moles of [tex]\( \text{KMnO}_4 \)[/tex].
- For each 2 moles of [tex]\( \text{KMnO}_4 \)[/tex], 8 moles of [tex]\( \text{H}_2\text{O} \)[/tex] are produced.

2. Setting up the ratio:
- The ratio of [tex]\( \text{H}_2\text{O} \)[/tex] to [tex]\( \text{KMnO}_4 \)[/tex] is given by [tex]\( \frac{8 \, \text{mol} \, \text{H}_2\text{O}}{2 \, \text{mol} \, \text{KMnO}_4} \)[/tex].
- Simplifying this ratio, [tex]\( \frac{8 \, \text{mol} \, \text{H}_2\text{O}}{2 \, \text{mol} \, \text{KMnO}_4} = 4 \, \text{mol} \, \text{H}_2\text{O} / 1 \, \text{mol} \, \text{KMnO}_4 \)[/tex].

3. Calculating the amount of [tex]\( \text{H}_2\text{O} \)[/tex] produced:
- We need to multiply the given moles of [tex]\( \text{KMnO}_4 \)[/tex] by the simplified ratio.
- Calculation: [tex]\( 3.45 \, \text{mol} \, \text{KMnO}_4 \times 4 \, \text{mol} \, \text{H}_2\text{O} / 1 \, \text{mol} \, \text{KMnO}_4 \)[/tex].

4. Performing the multiplication:
- This yields [tex]\( 3.45 \times 4 = 13.8 \, \text{mol} \, \text{H}_2\text{O} \)[/tex].

In summary, your initial setup was correct:

- You correctly used the ratio [tex]\( \frac{8 \, \text{mol} \, \text{H}_2\text{O}}{2 \, \text{mol} \, \text{KMnO}_4} \)[/tex].
- Simplified it to [tex]\( 4 \, \text{mol} \, \text{H}_2\text{O} \)[/tex] per [tex]\( 1 \, \text{mol} \, \text{KMnO}_4 \)[/tex].
- Correctly multiplied [tex]\( 3.45 \, \text{mol} \, \text{KMnO}_4 \)[/tex] by [tex]\( 4 \)[/tex] to get [tex]\( 13.8 \, \text{mol} \, \text{H}_2\text{O} \)[/tex].

Therefore, you set up the equation correctly and executed the calculation correctly, obtaining the correct answer.
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