To determine the mole ratio of aluminum (Al) to aluminum oxide (Al₂O₃) in the given chemical reaction, we first need to examine the balanced equation:
[tex]\[3 \text{Al} + 3 \text{NH}_4\text{ClO}_4 \rightarrow \text{Al}_2\text{O}_3 + \text{AlCl}_3 + 3 \text{NO} + 6 \text{H}_2\text{O}\][/tex]
This balanced equation tells us the stoichiometric relationship between the reactants and products. Let's focus on the species of interest:
- Aluminum (Al)
- Aluminum oxide (Al₂O₃)
From the balanced equation, we see that:
- 3 moles of Al react.
- 1 mole of Al₂O₃ is produced.
To find the mole ratio of Al to Al₂O₃, we consider the coefficients in front of each species in the equation.
The coefficient for Al is 3, and the coefficient for Al₂O₃ is 1.
Therefore, the mole ratio of Al to Al₂O₃ is:
[tex]\[
\frac{3 \, \text{moles of Al}}{1 \, \text{mole of Al}_2\text{O}_3}
\][/tex]
This simplifies to:
[tex]\[
3:1
\][/tex]
In decimal form, this ratio is 3.0.
