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Which polynomial correctly combines the like terms and puts the given polynomial in standard form?

Given polynomial:
[tex]\[ \frac{1}{3} x + 8 x^4 - \frac{2}{3} x^2 - x \][/tex]

A. [tex]\( 8 x^4 - \frac{1}{3} x^2 - x \)[/tex]
B. [tex]\( 8 x^4 + \frac{2}{3} x^2 + \frac{2}{3} x \)[/tex]
C. [tex]\( 8 x^4 - \frac{2}{3} x^2 - \frac{2}{3} x \)[/tex]
D. [tex]\( 8 x^4 - \frac{2}{3} x^2 - x \)[/tex]


Sagot :

To combine the like terms and put the given polynomial [tex]\(\frac{1}{3} x+8 x^4-\frac{2}{3} x^2-x\)[/tex] in standard form, follow these steps:

1. Identify and group the like terms in the polynomial. Here, like terms are terms that have the same variable raised to the same power.
- [tex]\(\frac{1}{3} x\)[/tex] and [tex]\(-x\)[/tex] are like terms because they both have [tex]\(x\)[/tex] raised to the first power.
- The term [tex]\(8x^4\)[/tex] is already in its simplest form.
- The term [tex]\(-\frac{2}{3} x^2\)[/tex] is also already in its simplest form.

2. Combine the like terms:
- Combine [tex]\(\frac{1}{3} x\)[/tex] and [tex]\(-x\)[/tex]:
[tex]\[\frac{1}{3} x - x\][/tex]

To combine these, it's often helpful to rewrite [tex]\(-x\)[/tex] as a fraction with a common denominator:
[tex]\[\frac{1}{3} x - \frac{3}{3} x = \frac{1 - 3}{3} x = -\frac{2}{3} x\][/tex]

3. Write the polynomial in standard form. The standard form of a polynomial is written from the highest degree term to the lowest degree term:
[tex]\[8x^4 - \frac{2}{3} x^2 - \frac{2}{3} x\][/tex]

Therefore, the polynomial that correctly combines the like terms and puts the polynomial in standard form is:
[tex]\[8x^4 - \frac{2}{3} x^2 - \frac{2}{3} x\][/tex]

Among the choices given:
1. [tex]\(8 x^4-\frac{1}{3} x^2-x\)[/tex]
2. [tex]\(8 x^4+\frac{2}{3} x^2+\frac{2}{3} x\)[/tex]
3. [tex]\(8 x^4-\frac{2}{3} x^2-\frac{2}{3} x\)[/tex]
4. [tex]\(8 x^4-\frac{2}{3} x^2-x\)[/tex]

The correct answer is:
[tex]\[8 x^4-\frac{2}{3} x^2-\frac{2}{3} x\][/tex]