Answered

Discover a wealth of knowledge at Westonci.ca, where experts provide answers to your most pressing questions. Discover a wealth of knowledge from experts across different disciplines on our comprehensive Q&A platform. Experience the convenience of finding accurate answers to your questions from knowledgeable experts on our platform.

How many grams of [tex]H_3PO_3[/tex] would be produced from the complete reaction of [tex]92.3 \, \text{g} \, P_2O_3[/tex]?

[tex]P_2O_3 + 3H_2O \rightarrow 2H_3PO_3[/tex]

Given:
[tex]92.3 \, \text{g} \, P_2O_3 \times \left( \frac{1 \, \text{mol} \, P_2O_3}{109.94 \, \text{g} \, P_2O_3} \right) \times \left( \frac{2 \, \text{mol} \, H_3PO_3}{1 \, \text{mol} \, P_2O_3} \right) \times \left( \frac{82.00 \, \text{g} \, H_3PO_3}{1 \, \text{mol} \, H_3PO_3} \right)[/tex]

Calculate the amount of [tex]H_3PO_3[/tex] produced.

Sagot :

GinnyAnswer
To find out how many grams of [tex]\( H_3PO_3 \)[/tex] would be produced from the complete reaction of 92.3 grams of [tex]\( P_2O_3 \)[/tex], we will follow these steps:

1. Determine the moles of [tex]\( P_2O_3 \)[/tex] in 92.3 grams:
- Given:
- Mass of [tex]\( P_2O_3 \)[/tex] = 92.3 grams
- Molar mass of [tex]\( P_2O_3 \)[/tex] = 109.94 grams per mole
- Formula to find moles:
[tex]\[ \text{Moles of } P_2O_3 = \frac{\text{Mass of } P_2O_3}{\text{Molar mass of } P_2O_3} \][/tex]
- Calculation:
[tex]\[ \text{Moles of } P_2O_3 = \frac{92.3 \, \text{grams}}{109.94 \, \text{grams per mole}} \approx 0.8395 \, \text{moles} \][/tex]

2. Use the balanced chemical equation to find the moles of [tex]\( H_3PO_3 \)[/tex] formed:
- From the balanced chemical equation:
[tex]\[ P_2O_3 + 3 H_2O \rightarrow 2 H_3PO_3 \][/tex]
We see that 1 mole of [tex]\( P_2O_3 \)[/tex] produces 2 moles of [tex]\( H_3PO_3 \)[/tex].
- Using the moles of [tex]\( P_2O_3 \)[/tex] we calculated:
[tex]\[ \text{Moles of } H_3PO_3 = 0.8395 \, \text{moles of } P_2O_3 \times 2 = 1.6791 \, \text{moles} \][/tex]

3. Calculate the mass of [tex]\( H_3PO_3 \)[/tex] produced:
- Given:
- Molar mass of [tex]\( H_3PO_3 \)[/tex] = 82.00 grams per mole
- Formula to find mass:
[tex]\[ \text{Mass of } H_3PO_3 = \text{Moles of } H_3PO_3 \times \text{Molar mass of } H_3PO_3 \][/tex]
- Calculation:
[tex]\[ \text{Mass of } H_3PO_3 = 1.6791 \, \text{moles} \times 82.00 \, \text{grams per mole} \approx 137.69 \, \text{grams} \][/tex]

So, the mass of [tex]\( H_3PO_3 \)[/tex] produced from the complete reaction of 92.3 grams of [tex]\( P_2O_3 \)[/tex] is approximately 137.69 grams.
Thanks for stopping by. We strive to provide the best answers for all your questions. See you again soon. We hope our answers were useful. Return anytime for more information and answers to any other questions you have. Your questions are important to us at Westonci.ca. Visit again for expert answers and reliable information.