Welcome to Westonci.ca, where you can find answers to all your questions from a community of experienced professionals. Join our Q&A platform to connect with experts dedicated to providing precise answers to your questions in different areas. Connect with a community of professionals ready to help you find accurate solutions to your questions quickly and efficiently.
Sagot :
To find out how many grams of [tex]\( H_3PO_3 \)[/tex] would be produced from the complete reaction of 92.3 grams of [tex]\( P_2O_3 \)[/tex], we will follow these steps:
1. Determine the moles of [tex]\( P_2O_3 \)[/tex] in 92.3 grams:
- Given:
- Mass of [tex]\( P_2O_3 \)[/tex] = 92.3 grams
- Molar mass of [tex]\( P_2O_3 \)[/tex] = 109.94 grams per mole
- Formula to find moles:
[tex]\[ \text{Moles of } P_2O_3 = \frac{\text{Mass of } P_2O_3}{\text{Molar mass of } P_2O_3} \][/tex]
- Calculation:
[tex]\[ \text{Moles of } P_2O_3 = \frac{92.3 \, \text{grams}}{109.94 \, \text{grams per mole}} \approx 0.8395 \, \text{moles} \][/tex]
2. Use the balanced chemical equation to find the moles of [tex]\( H_3PO_3 \)[/tex] formed:
- From the balanced chemical equation:
[tex]\[ P_2O_3 + 3 H_2O \rightarrow 2 H_3PO_3 \][/tex]
We see that 1 mole of [tex]\( P_2O_3 \)[/tex] produces 2 moles of [tex]\( H_3PO_3 \)[/tex].
- Using the moles of [tex]\( P_2O_3 \)[/tex] we calculated:
[tex]\[ \text{Moles of } H_3PO_3 = 0.8395 \, \text{moles of } P_2O_3 \times 2 = 1.6791 \, \text{moles} \][/tex]
3. Calculate the mass of [tex]\( H_3PO_3 \)[/tex] produced:
- Given:
- Molar mass of [tex]\( H_3PO_3 \)[/tex] = 82.00 grams per mole
- Formula to find mass:
[tex]\[ \text{Mass of } H_3PO_3 = \text{Moles of } H_3PO_3 \times \text{Molar mass of } H_3PO_3 \][/tex]
- Calculation:
[tex]\[ \text{Mass of } H_3PO_3 = 1.6791 \, \text{moles} \times 82.00 \, \text{grams per mole} \approx 137.69 \, \text{grams} \][/tex]
So, the mass of [tex]\( H_3PO_3 \)[/tex] produced from the complete reaction of 92.3 grams of [tex]\( P_2O_3 \)[/tex] is approximately 137.69 grams.
1. Determine the moles of [tex]\( P_2O_3 \)[/tex] in 92.3 grams:
- Given:
- Mass of [tex]\( P_2O_3 \)[/tex] = 92.3 grams
- Molar mass of [tex]\( P_2O_3 \)[/tex] = 109.94 grams per mole
- Formula to find moles:
[tex]\[ \text{Moles of } P_2O_3 = \frac{\text{Mass of } P_2O_3}{\text{Molar mass of } P_2O_3} \][/tex]
- Calculation:
[tex]\[ \text{Moles of } P_2O_3 = \frac{92.3 \, \text{grams}}{109.94 \, \text{grams per mole}} \approx 0.8395 \, \text{moles} \][/tex]
2. Use the balanced chemical equation to find the moles of [tex]\( H_3PO_3 \)[/tex] formed:
- From the balanced chemical equation:
[tex]\[ P_2O_3 + 3 H_2O \rightarrow 2 H_3PO_3 \][/tex]
We see that 1 mole of [tex]\( P_2O_3 \)[/tex] produces 2 moles of [tex]\( H_3PO_3 \)[/tex].
- Using the moles of [tex]\( P_2O_3 \)[/tex] we calculated:
[tex]\[ \text{Moles of } H_3PO_3 = 0.8395 \, \text{moles of } P_2O_3 \times 2 = 1.6791 \, \text{moles} \][/tex]
3. Calculate the mass of [tex]\( H_3PO_3 \)[/tex] produced:
- Given:
- Molar mass of [tex]\( H_3PO_3 \)[/tex] = 82.00 grams per mole
- Formula to find mass:
[tex]\[ \text{Mass of } H_3PO_3 = \text{Moles of } H_3PO_3 \times \text{Molar mass of } H_3PO_3 \][/tex]
- Calculation:
[tex]\[ \text{Mass of } H_3PO_3 = 1.6791 \, \text{moles} \times 82.00 \, \text{grams per mole} \approx 137.69 \, \text{grams} \][/tex]
So, the mass of [tex]\( H_3PO_3 \)[/tex] produced from the complete reaction of 92.3 grams of [tex]\( P_2O_3 \)[/tex] is approximately 137.69 grams.
Thank you for your visit. We are dedicated to helping you find the information you need, whenever you need it. Thanks for using our service. We're always here to provide accurate and up-to-date answers to all your queries. Stay curious and keep coming back to Westonci.ca for answers to all your burning questions.