Welcome to Westonci.ca, the Q&A platform where your questions are met with detailed answers from experienced experts. Join our Q&A platform to connect with experts dedicated to providing accurate answers to your questions in various fields. Get detailed and accurate answers to your questions from a dedicated community of experts on our Q&A platform.

Two sides and an angle are given below. Determine whether the given information results in one​ triangle, two​ triangles, or no triangle at all. Solve any resulting​ triangle(s).
a=8, c=6, C=10 degrees

Sagot :

Answer:

  • 2 triangles
  • A = 13.4°, B = 156.6°, b = 13.7
  • A = 166.6°, B = 3.4°, b = 2.04

Step-by-step explanation:

You want to know how many triangles are specified by sides and angle of a = 8, c = 6, and C = 10°, and the solutions for each.

SSA

When two sides and an adjacent angle are specified, the number of triangles may be 0, 1, or 2. If the specified angle is opposite the longer of the two sides, then there will always be one triangle.

If the specified angle is opposite the shorter of the two sides, as here, the number of triangles depends on the relation between the given values:

  short / long < sin(θ) ⇒ 0 triangles
  short / long = sin(θ) ⇒ 1 right triangle
  short / long > sin(θ) ⇒ 2 triangles

Here, we have 6/8 > sin(10°), so there will be two solutions.

Second angle

The law of sines is used to find the angle opposite the other given side.

  [tex]\dfrac{\sin(A)}{a}=\dfrac{\sin(C)}{c}\\\\A=\arcsin\left(\sin(C)\cdot\dfrac{a}{c}\right)\\\\A=\arcsin(\dfrac{4}{3}\sin(10^\circ))\approx13.4^\circ[/tex]

In this application, the angle whose sine is 4/3sin(10°) may be the supplement of this value as well.

  A' = 180° -A = 166.6°

Third angle

The third angle in the triangle will have the value that brings the total to 180°:

  B = 180° -10° -A = 156.6°

  B' = 180° -10° -A' = 3.4°

Third side

The law of sines is used again to find the length of the third side of the triangle.

  [tex]\dfrac{b}{\sin(B)}=\dfrac{c}{\sin(C)}\\\\b=c\cdot\dfrac{\sin(B)}{\sin(C)}[/tex]

Then for the possible values of angle B, the possible values of side b are ...

  [tex]b=6\cdot\dfrac{\sin(156.6^\circ)}{\sin(10^\circ)}\approx13.7\\\\b'=6\cdot\dfrac{\sin(3.4^\circ)}{\sin(10^\circ)}\approx2.04[/tex]

Solutions

In summary, the solutions for the two possible triangles are ...

  • A = 13.4°, B = 156.6°, b = 13.7
  • A = 166.6°, B = 3.4°, b = 2.04

__

Additional comment

We have given the side b=2.04 to two decimal places, because a side length of 2.0 would make that triangle look like a straight line segment.

View image sqdancefan