At Westonci.ca, we connect you with experts who provide detailed answers to your most pressing questions. Start exploring now! Our platform offers a seamless experience for finding reliable answers from a network of experienced professionals. Connect with a community of professionals ready to help you find accurate solutions to your questions quickly and efficiently.
Sagot :
To determine how much work the electric field does in moving a charge, we use the formula for electrical work done:
[tex]\[ W = q \Delta V \][/tex]
Here's the step-by-step solution:
1. Identify the given values:
- The charge [tex]\( q \)[/tex] is [tex]\( -7.3 \)[/tex] microcoulombs ([tex]\(\mu C\)[/tex]). Since 1 microcoulomb ([tex]\( \mu C \)[/tex]) is [tex]\( 1 \times 10^{-6} \)[/tex] coulombs, we convert the charge to coulombs:
[tex]\[ q = -7.3 \times 10^{-6} \text{ C} \][/tex]
- The potential difference [tex]\( \Delta V \)[/tex] is [tex]\( +65 \)[/tex] volts (V).
2. Substitute the given values into the formula:
[tex]\[ W = q \Delta V \][/tex]
[tex]\[ W = (-7.3 \times 10^{-6} \text{ C}) \times (65 \text{ V}) \][/tex]
3. Calculate the work done:
The product of the charge and the potential difference gives:
[tex]\[ W = -0.00047450000000000004 \text{ joules} \][/tex]
4. Express the answer with two significant figures:
Since we need the result to two significant figures, we round the answer appropriately:
[tex]\[ W \approx -4.7 \times 10^{-4} \text{ J} \][/tex]
So the electric field does approximately [tex]\( -4.7 \times 10^{-4} \)[/tex] joules of work in moving a [tex]\( -7.3 \mu C \)[/tex] charge from ground to a point whose potential is [tex]\( +65 V \)[/tex] higher.
[tex]\[ W = q \Delta V \][/tex]
Here's the step-by-step solution:
1. Identify the given values:
- The charge [tex]\( q \)[/tex] is [tex]\( -7.3 \)[/tex] microcoulombs ([tex]\(\mu C\)[/tex]). Since 1 microcoulomb ([tex]\( \mu C \)[/tex]) is [tex]\( 1 \times 10^{-6} \)[/tex] coulombs, we convert the charge to coulombs:
[tex]\[ q = -7.3 \times 10^{-6} \text{ C} \][/tex]
- The potential difference [tex]\( \Delta V \)[/tex] is [tex]\( +65 \)[/tex] volts (V).
2. Substitute the given values into the formula:
[tex]\[ W = q \Delta V \][/tex]
[tex]\[ W = (-7.3 \times 10^{-6} \text{ C}) \times (65 \text{ V}) \][/tex]
3. Calculate the work done:
The product of the charge and the potential difference gives:
[tex]\[ W = -0.00047450000000000004 \text{ joules} \][/tex]
4. Express the answer with two significant figures:
Since we need the result to two significant figures, we round the answer appropriately:
[tex]\[ W \approx -4.7 \times 10^{-4} \text{ J} \][/tex]
So the electric field does approximately [tex]\( -4.7 \times 10^{-4} \)[/tex] joules of work in moving a [tex]\( -7.3 \mu C \)[/tex] charge from ground to a point whose potential is [tex]\( +65 V \)[/tex] higher.
Thanks for using our service. We aim to provide the most accurate answers for all your queries. Visit us again for more insights. We hope you found this helpful. Feel free to come back anytime for more accurate answers and updated information. We're glad you visited Westonci.ca. Return anytime for updated answers from our knowledgeable team.