Welcome to Westonci.ca, the ultimate question and answer platform. Get expert answers to your questions quickly and accurately. Get expert answers to your questions quickly and accurately from our dedicated community of professionals. Get quick and reliable solutions to your questions from a community of experienced experts on our platform.

3) In the following numbers, the irrational number is:

A. [tex]\sqrt{16} - \sqrt{9}[/tex]
B. [tex]\frac{3}{4}[/tex]
C. 0.3333
D. [tex]2 + \sqrt{3}[/tex]


Sagot :

To find out the irrational number among the given options, let's analyze each option step by step.

Option A: [tex]\(\sqrt{16} - \sqrt{9}\)[/tex]

- [tex]\(\sqrt{16} = 4\)[/tex]
- [tex]\(\sqrt{9} = 3\)[/tex]
- Therefore, [tex]\(\sqrt{16} - \sqrt{9} = 4 - 3 = 1\)[/tex]

Since 1 is a rational number, Option A is not an irrational number.

Option B: [tex]\(\frac{3}{4}\)[/tex]

- [tex]\(\frac{3}{4}\)[/tex] is already a fraction of two integers (3 and 4), which means it's a rational number.

So, Option B is not an irrational number.

Option C: 0.3333

- 0.3333 is a decimal representation that can be approximated by a fraction, specifically [tex]\(\frac{3333}{10000}\)[/tex].

Since 0.3333 can be represented as a fraction, it is a rational number.

Option D: [tex]\(2 + \sqrt{3}\)[/tex]

- [tex]\(2\)[/tex] is a rational number.
- [tex]\(\sqrt{3}\)[/tex] is an irrational number because it cannot be expressed as a fraction of two integers.
- The sum of a rational number and an irrational number is always irrational.

Thus, [tex]\(2 + \sqrt{3}\)[/tex] is an irrational number.

Given this analysis, the irrational number among the options is:

D) [tex]\(2 + \sqrt{3}\)[/tex]

Hence, the correct answer is [tex]\(4\)[/tex].